Problem 133
Question
Use the strategy for solving word problems, modeling the verbal conditions of the problem with a linear inequality. The toll to a bridge is \(\$ 3.00 .\) A three-month pass costs \(\$ 7.50\) and reduces the toll to \(\$ 0.50 .\) A six-month pass costs \(\$ 30\) and permits crossing the bridge for no additional fee. How many crossings per three-month period does it take for the three month pass to be the best deal?
Step-by-Step Solution
Verified Answer
The three-month pass becomes the best deal for crossing the bridge when one has to make more than three crossings within a three-month period.
1Step 1: Formulate the cost function for each scenario
For a regular toll without pass, the cost per crossing is $3. So, the total cost of crossing the bridge n times would be 3n. The cost for a three-month pass is $7.5 and the cost per crossing is reduced to $0.5. Total cost would therefore be 7.5 + 0.5n. A six-month pass costs $30 with no additional fee per crossing. Hence the cost is constant at 30.
2Step 2: Set up the inequality
Since the goal is to find out the number of crossings for which the three-month pass is the best deal, an inequality needs to be set up comparing the cost of three-month pass and the cost of daily pass. Therefore, the inequality is: \(3n > 7.5 + 0.5n\)
3Step 3: Solving the inequality
First simplify the above inequality by subtracting \(0.5n\) from both sides: \(2.5n > 7.5\). Dividing both sides by 2.5 gives: \(n >3\)
4Step 4: Interpret the result
The inequality \(n > 3\) implies that the three-month pass becomes a better deal when one needs to cross the bridge more than three times within a three-month period.
Key Concepts
Word ProblemsCost FunctionSolving InequalitiesMathematical Modeling
Word Problems
Word problems are often used in math to represent real-life situations through mathematical expressions. Solving word problems involves understanding the problem statement, identifying the necessary information, and translating the word problem into a mathematical expression or equation.
To successfully solve the given bridge toll problem, one must interpret the scenarios:
To successfully solve the given bridge toll problem, one must interpret the scenarios:
- The regular toll costs $3 per crossing.
- A three-month pass costs $7.50, reducing the toll to $0.50 per crossing.
- A six-month pass costs $30 and eliminates per-crossing fees.
Cost Function
The cost function helps to calculate expenses associated with different options based on variable conditions — in this case, the number of bridge crossings. A cost function represents this relationship mathematically.
For the regular toll without a pass, the cost function is simple:
For the regular toll without a pass, the cost function is simple:
- Total cost = \(3 * n, where \(n\) is the number of crossings.
- Total cost = \)7.50 + \(0.50 * n
- Total cost = \)30
Solving Inequalities
Solving inequalities involves finding the values of a variable that make one expression greater than or less than another. In the context of this problem, the inequality helps identify when one toll option is cheaper than the other.
The inequality to determine when the three-month pass is a better deal than paying the regular toll is:
The inequality to determine when the three-month pass is a better deal than paying the regular toll is:
- \(3n > 7.5 + 0.5n\)
- Subtract \(0.5n\) from both sides: \(2.5n > 7.5\)
- Dividing by 2.5: \(n > 3\)
Mathematical Modeling
Mathematical modeling transforms real-world problems into mathematical representations. With modeling, you can analyze relationships, predict outcomes, and make decisions based on mathematical results.
The bridge toll problem uses a linear inequality model to answer practical questions about cost-effectiveness. Key steps in mathematical modeling include:
The bridge toll problem uses a linear inequality model to answer practical questions about cost-effectiveness. Key steps in mathematical modeling include:
- Defining the problem and variables: crossing fee, pass cost, etc.
- Creating mathematical expressions or equations: cost functions for each scenario.
- Setting up equations or inequalities to compare options: formulating \(3n > 7.5 + 0.5n\).
- Solving to interpret outcomes: finding \(n > 3\) indicates use of a three-month pass is cheaper for more than three crossings.
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