Problem 133
Question
In Exercises 131 - 134, write the trigonometric expression as an algebraic expression. \( \cos\left(2 \arcsin x\right) \)
Step-by-Step Solution
Verified Answer
\(\cos(2 \arcsin x) = 1 - 2x^2\)
1Step 1: Setup
Let's consider the double-angle identity in the form of cosine, which is \( \cos(2a) = 1 - 2 \sin^2(a) \). Here, \( a \) is the arcsin of \( x \), or \( a = \arcsin x \), which means \( \sin a = x \). Now, we substitute \( a \) for \( \arcsin x \) in the identity.
2Step 2: Substitute
Now, if we replace `a` in our identity with \(\arcsin x\), we get \(\cos(2 \arcsin x) = 1 - 2 \sin^2(\arcsin x)\). The term \(\sin(\arcsin x)\) can be simplified to \(x\), so we plug this into the equation.
3Step 3: Simplify
By substituting \(x\) for \(\sin(\arcsin x)\), we finally get \(\cos(2 \arcsin x) = 1 - 2x^2\). This is the final step to convert the given trigonometric expression into an algebraic expression.
Key Concepts
Double-Angle IdentitiesAlgebraic ExpressionsInverse Trigonometric Functions
Double-Angle Identities
Double-angle identities are powerful tools in trigonometry. They allow us to express trigonometric functions involving double angles in terms of single angles. This is particularly useful when simplifying complex expressions.
One of the commonly used double-angle identities is for cosine, given by:
The identity shows that by using a known angle 'a', you can calculate the cosine of its double '2a' through its corresponding sine value. This process significantly simplifies tasks in trigonometry where calculating angles of twice the magnitude is required.
One of the commonly used double-angle identities is for cosine, given by:
- \( \cos(2a) = 1 - 2 \sin^2(a) \)
The identity shows that by using a known angle 'a', you can calculate the cosine of its double '2a' through its corresponding sine value. This process significantly simplifies tasks in trigonometry where calculating angles of twice the magnitude is required.
Algebraic Expressions
Algebraic expressions are a way to write numbers and variables in a formulaic manner to solve problems algebraically. They often involve variables, constants, and arithmetic operations.
Converting trigonometric expressions into algebraic forms can often simplify the evaluation of these expressions.
For example, in the expression \( \cos(2 \arcsin x) \), we use a double-angle identity to rewrite it as an algebraic expression. Once the identity \( \cos(2a) = 1 - 2 \sin^2(a) \) is applied and \( a \) is substituted with \( \arcsin x \), we simplify it further as:
Converting trigonometric expressions into algebraic forms can often simplify the evaluation of these expressions.
For example, in the expression \( \cos(2 \arcsin x) \), we use a double-angle identity to rewrite it as an algebraic expression. Once the identity \( \cos(2a) = 1 - 2 \sin^2(a) \) is applied and \( a \) is substituted with \( \arcsin x \), we simplify it further as:
- \( \cos(2 \arcsin x) = 1 - 2x^2 \)
Inverse Trigonometric Functions
Inverse trigonometric functions are functions that reverse the effect of the original trigonometric functions. They allow us to find angles when given trigonometric ratios.
Functions like arcsine, arccosine, and arctangent play a crucial role in finding angles from specific values in trigonometry.
This angle is then plugged into trigonometric identities, such as the double-angle identity, to facilitate the conversion of trigonometric expressions into algebraic ones. Inverse trigonometric functions are indispensable in calculus and trigonometry for solving equations and evaluating expressions involving angles.
Functions like arcsine, arccosine, and arctangent play a crucial role in finding angles from specific values in trigonometry.
- \( \arcsin(x) \), for example, finds an angle whose sine is \( x \).
This angle is then plugged into trigonometric identities, such as the double-angle identity, to facilitate the conversion of trigonometric expressions into algebraic ones. Inverse trigonometric functions are indispensable in calculus and trigonometry for solving equations and evaluating expressions involving angles.
Other exercises in this chapter
Problem 132
In Exercises 131 - 134, write the trigonometric expression as an algebraic expression. \( \cos\left(2 \arccos x\right) \)
View solution Problem 132
In Exercises 129 - 132, fill in the blanks. (Note:The notation \( x \rightarrow c^+ \) indicates that \( x \) approaches \( c \) from the right and \( x \righta
View solution Problem 133
In Exercises 133 - 138, determine whether or not the equation is an identity, and give a reason for your answer. \( \cos \theta = \sqrt{1 - \sin^2 \theta} \)
View solution Problem 134
In Exercises 131 - 134, write the trigonometric expression as an algebraic expression. \( \sin\left(2 \arccos x\right) \)
View solution