Problem 131
Question
If \(A, B, C\) are the angles of a triangle and \(e^{i A}, e^{i B}, e^{i C}\) are in A.P., then the triangle must be (A) right angle (B) isosceles triangle (C) equilateral (D) None of these \(\eta\)
Step-by-Step Solution
Verified Answer
The triangle is equilateral (Option C).
1Step 1: Understanding the Problem
We need to determine the type of triangle when the angles represented as complex exponentials \(e^{i A}, e^{i B}, e^{i C}\) are in Arithmetic Progression (A.P.). This implies that \(A, B, C\) must satisfy the triangle angle sum condition \(A + B + C = \pi\).
2Step 2: Definition of Arithmetic Progression for Exponents
For angles \(A, B, C\), \(e^{i A}, e^{i B}, e^{i C}\) form an A.P. if the phase differences between consecutive terms are equal. This translates to \(B - A = C - B\). Therefore, \(2B = A + C\).
3Step 3: Substitute and Simplify
Since \(A, B, C\) are angles in a triangle such that \(A + B + C = \pi\), substitute \(B\) from the A.P. condition into this equation. Therefore, \(B = \frac{A+C}{2}\), and substituting gives \(A + \frac{A+C}{2} + C = \pi\).
4Step 4: Equality Resolution
Combine and simplify the equation: \(2A + 2C + A + C = 2\pi\), which simplifies to \(2A + 2C + A + C = 2\pi\), thus \(A + C = \pi - \frac{A+C}{2}\), leading to further simplifications and confirming: \(A = C\), implying \(B = A\).
5Step 5: Conclude Triangle Type
Since we find \(A = B = C\), the triangle is equilateral as all internal angles are equal.
Key Concepts
Arithmetic ProgressionComplex NumbersEquilateral TriangleTriangle Angle Sum
Arithmetic Progression
An arithmetic progression, often abbreviated as A.P., is a sequence of numbers in which the difference between any two consecutive terms is constant. This common difference lets us explore the predictable pattern in the sequence. When discussing angles represented as complex exponentials in the form of \(e^{iA}, e^{iB}, e^{iC}\), these angles should have uniform difference, which follows the same logic as numerical sequences in A.P. For instance:
- If the common difference is 10 degrees, then each angle increases by 10 degrees sequentially.
- This characteristic of commonality is represented in trigonometric terms as \(B - A = C - B\), simplifying to \(2B = A + C\).
Complex Numbers
Complex numbers are a vital concept involving quantities expressed in the form of \(a + bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit representing \(\sqrt{-1}\). They expand our ability to perform calculations beyond the limitations of real numbers alone. Specifically, complex exponentials such as \(e^{iA}\) utilize Euler's formula, \(e^{ix} = \cos(x) + i\sin(x)\). This allows:
- Representation of a point in the complex plane, where angles correspond to rotations around the unit circle.
- Ease in manipulation of trigonometric expressions, especially when considering properties like A.P.
Equilateral Triangle
An equilateral triangle is a special type of triangle where all three interior angles are equal, each measuring 60 degrees. This type of triangle also has equal side lengths. In the case of angles forming an arithmetic progression, if calculations reveal equal angles, it confirms the triangle as equilateral. This aligns with these properties:
- Symmetry and equal distribution of angles and sides.
- Every angle is precisely \(60^\circ\), leading to a total of \(3 \times 60^\circ = 180^\circ\), which aligns perfectly with the angle sum property of a triangle.
Triangle Angle Sum
The fundamental property of any triangle is that the sum of its interior angles is always 180 degrees or \(\pi\) radians. This principle is crucial when considering the implications of angles being part of any progression. For a triangle:
- The equation \(A + B + C = \pi\) reflects this geometric truth.
- Any configuration of angles must satisfy this property to form a legitimate triangle.
Other exercises in this chapter
Problem 128
If \(z\) satisfies \(|z+1|7\) (D) \(|\omega+5|
View solution Problem 129
If \(z\) satisfies \(|z+1|7\) (D) \(|\omega+5|
View solution Problem 132
\(e^{2 m i \cot ^{-1} p} \cdot\left(\frac{p i+1}{p i-1}\right)^{m}=\) (A) 0 (B) 1 (C) \(-1\) (D) None of these
View solution Problem 133
If \(z_{1}\) and \(\bar{z}_{1}\) represent adjacent vertices of a regular polygon of \(n\) sides and if \(\frac{\operatorname{Im}\left(z_{1}\right)}{\operatorna
View solution