Problem 13
Question
You drive on Interstate 10 from San Antonio to Houston, half the time at \(55 \mathrm{~km} / \mathrm{h}\) and the other half at \(90 \mathrm{~km} / \mathrm{h}\). On the way back you travel half the distance at \(55 \mathrm{~km} / \mathrm{h}\) and the other half at \(90 \mathrm{~km} / \mathrm{h}\). What is your average speed (a) from San Antonio to Houston, (b) from Houston back to San Antonio, and (c) for the entire trip? (d) What is your average velocity for the entire trip? (e) Sketch \(x\) versus \(t\) for (a), assuming the motion is all in the positive \(x\) direction. Indicate how the average velocity can be found on the sketch.
Step-by-Step Solution
Verified Answer
(a) 68.28 km/h; (b) 68.28 km/h; (c) 68.28 km/h; (d) 0 km/h.
1Step 1: Calculate Average Speed from San Antonio to Houston
To find the average speed when traveling half the time at different speeds, use the formula \( v_{avg} = \left( \frac{2v_1v_2}{v_1 + v_2} \right) \). Here, \(v_1 = 55\mathrm{~km/h}\) and \(v_2 = 90\mathrm{~km/h}\).Substitute the values:\[v_{avg} = \frac{2 \times 55 \times 90}{55 + 90} = \frac{9900}{145} = 68.28 \mathrm{~km/h}.\]
2Step 2: Calculate Average Speed from Houston to San Antonio
To find the average speed for traveling equal distances at different speeds, use the formula:\[v_{avg} = \frac{2d}{\frac{d}{v_1} + \frac{d}{v_2}} = \frac{2v_1v_2}{v_1 + v_2}.\]As it turns out, this situation also leads to the same average since it's equivalent to calculating for half the time:\[v_{avg} = \frac{2 \times 55 \times 90}{145} = 68.28 \mathrm{~km/h}.\]
3Step 3: Calculate Average Speed for Entire Trip
The entire trip consists of each journey segment. Since the total distance traveled is the same in both directions with equal time at different speeds on mixed criteria, use:\[v_{avg} = \frac{2 \times 68.28}{2} = 68.28 \mathrm{~km/h}.\]
4Step 4: Calculate Average Velocity for the Entire Trip
The average velocity for a round trip where the start and end points are the same is always zero, as the displacement is zero.Therefore, average velocity \(v = 0 \mathrm{~km/h}.\)
5Step 5: Sketch X versus T for Part (a)
Create a sketch of position \(x\) versus time \(t\) for the trip from San Antonio to Houston. Since you're moving in a positive direction throughout, the graph is an upward-sloping line. The slope is represented by the average speed of 68.28 km/h for this part of the journey.The average velocity can be found on this sketch as the overall slope of the line from starting point to final position, or rise over run, as x increases continuously.
Key Concepts
Average VelocityConstant SpeedRound TripDisplacement
Average Velocity
The concept of average velocity might initially seem similar to average speed, but they're distinct. Average velocity is defined as the total displacement divided by the total time of travel. In cases like a round trip, where you start and end at the same point, the displacement is zero. Hence, the average velocity is:
- Average velocity \(v_{avg} = \frac{\text{Displacement}}{\text{Total Time}}\).
- For a round trip resulting in zero displacement, \(v_{avg} = 0 \text{ km/h}\).
Constant Speed
Constant speed refers to the condition where an object covers equal distances in equal intervals of time without any variation. During a journey, maintaining a constant speed can simplify calculations and predictions about travel time.
- In real-world scenarios, factors such as traffic or road conditions can cause fluctuations in speed.
- When calculations are based on constant speed, travel time and average speed are straightforward to predict.
- Activities like cruise control in vehicles aim to maintain constant speed.
Round Trip
A round trip involves traveling to a destination and returning to the original point. For example, traveling from San Antonio to Houston and back is a classic round trip.
- In our example, the same speeds are used for half the time and half the distance in each direction.
- Round trips often show how average speed calculations differ from simple velocity because the return path must also be considered.
- Since the final position is the starting point, the overall displacement is zero.
Displacement
Displacement refers to the change in position from a starting point to a final point. It is a vector quantity, meaning it has both magnitude and direction.
- It is unrelated to the path taken and only considers the initial and final locations.
- In a complete round trip, like traveling from a city back to the same city, the displacement is zero.
- This is why, in the exercise, even though you drove hundreds of kilometers, the displacement calculation results in zero.
Other exercises in this chapter
Problem 7
Two trains, each having a speed of \(30 \mathrm{~km} / \mathrm{h},\) are headed at each other on the same straight track. A bird that can fly \(60 \mathrm{~km}
View solution Problem 9
In 1 km races, runner 1 on track 1 (with time \(2 \min .27 .95 \mathrm{~s}\) ) appears to be faster than runner 2 on track \(2(2 \min , 28.15 \mathrm{~s})\). Ho
View solution Problem 15
(a) If a particlc's position is given by \(x=4-12 t+3 t^{2}\) (where \(t\) is in seconds and \(x\) is in meters), what is its velocity at \(t=1 \mathrm{~s} ?(\m
View solution Problem 18
The position of a particle moving along an \(x\) axis is given by \(x=12 t^{2}-2 t^{3}\), where \(x\) is in meters and \(t\) is in seconds. Determine (a) the po
View solution