Problem 13
Question
Write the complex number in standard form and find its complex conjugate. $$-6 i+i^{2}$$
Step-by-Step Solution
Verified Answer
The complex number in standard form is \(-1 - 6i\) and its complex conjugate is \(-1 + 6i\).
1Step 1: Simplify the expression
Firstly, we know that \(i^{2} = -1\). Thus, by substituting this into the given expression, we get \(-6i + (-1)\). This simplifies to \(-1 - 6i\).
2Step 2: Write in standard form
The standard form of a complex number is \(a+bi\), where \(a\) and \(b\) are real numbers, and \(i\) is the imaginary unit. After simplifying, the complex number is already in standard form as \(-1 - 6i\), where \(a = -1\) and \(b = -6\).
3Step 3: Find the complex conjugate
The complex conjugate of a complex number is obtained by changing the sign of its imaginary part. If our complex number is \(-1 - 6i\), then its complex conjugate will be \(-1 + 6i\).
Key Concepts
Standard FormComplex ConjugateImaginary Unit
Standard Form
Complex numbers can often seem intimidating, but once you understand their structure, they become easy to work with. A complex number is traditionally expressed in what's called the "standard form": \(a + bi\). Here:
Breaking down more complicated expressions into standard form can often simplify calculations, helping you easily manipulate and understand complex numbers.
- \(a\) is the real part of the complex number.
- \(b\) is the factor of the imaginary part, which is attached to the imaginary unit \(i\).
- The real part \(a\) is \(-1\).
- The imaginary part \(b\) is \(-6\).
Breaking down more complicated expressions into standard form can often simplify calculations, helping you easily manipulate and understand complex numbers.
Complex Conjugate
A powerful tool in the realm of complex numbers is the "complex conjugate," which helps in simplification and division. The complex conjugate of a number is found by changing the sign of its imaginary part.
For a complex number like \(-1 - 6i\), the complex conjugate is simply \(-1 + 6i\).
This process is straightforward:
Multiplying a complex number by its conjugate can be used to eliminate the imaginary component, leaving us with a real number—an invaluable step in many calculations. In our case, multiplying \(-1 - 6i\) with its conjugate \(-1 + 6i\), yields a real number.
For a complex number like \(-1 - 6i\), the complex conjugate is simply \(-1 + 6i\).
This process is straightforward:
- Take the original complex number.
- Flip the sign of the imaginary part.
Multiplying a complex number by its conjugate can be used to eliminate the imaginary component, leaving us with a real number—an invaluable step in many calculations. In our case, multiplying \(-1 - 6i\) with its conjugate \(-1 + 6i\), yields a real number.
Imaginary Unit
At the heart of complex numbers lies the imaginary unit, denoted by \(i\). This small letter holds a very particular property: \(i^2 = -1\).
You might wonder why this property matters. Well, it allows us to extend numbers beyond the real number line in a logical way.
In calculations, like expressing \(-6i + i^2\), understanding \(i^2 = -1\) is key to simplifying expressions to their real and imaginary parts. Knowing this property, you can tackle complex expressions with confidence, as seen in converting the expression to \(-1 - 6i\), aiding understanding and calculation efficiency.
You might wonder why this property matters. Well, it allows us to extend numbers beyond the real number line in a logical way.
- \(i\) introduces a dimension perpendicular to the real numbers.
- It allows representation of numbers that are considered "imaginary," hence opening new ways of calculation and applications.
In calculations, like expressing \(-6i + i^2\), understanding \(i^2 = -1\) is key to simplifying expressions to their real and imaginary parts. Knowing this property, you can tackle complex expressions with confidence, as seen in converting the expression to \(-1 - 6i\), aiding understanding and calculation efficiency.
Other exercises in this chapter
Problem 13
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Find all real zeros of the function. $$f(x)=x^{4}-11 x^{2}+18$$
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Use long division to divide. Divisor \(x^{2}+1\) Dividend $$x^{3}-9$$
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