Problem 13
Question
Write each expression in radical form. Assume that all variables represent positive real numbers. $$\sqrt[5]{k^{2}}$$
Step-by-Step Solution
Verified Answer
Write as \( \sqrt[5]{k^{2}} \), which is the fifth root form of \( k^2. \)
1Step 1: Understand Radicals and Exponents
The expression \( \sqrt[5]{k^{2}} \) can be written in radical form or in exponential form. In radical form, it's already given as a fifth root. We'll understand that radicals are expressions with roots, and \( \sqrt[n]{x} = x^{1/n} \). Here, \( n = 5 \). So, \( \sqrt[5]{k^{2}} = (k^{2})^{1/5} \).
2Step 2: Convert to Exponential Form
We can express the radical \( \sqrt[5]{k^{2}} \) using exponents. The expression \( \sqrt[5]{k^{2}} \) means the fifth root of \( k^{2} \). This is equivalent to raising \( k^{2} \) to the power of \( \frac{1}{5} \), giving us the exponential form \( (k^{2})^{1/5} \).
3Step 3: Simplify the Expression
Next, apply the property of exponents \((a^m)^n = a^{m \cdot n}\) to the expression \( (k^{2})^{1/5} \). Multiply the exponents: \( 2 \times \frac{1}{5} = \frac{2}{5} \). Thus, the expression simplifies to \( k^{2/5} \ ext{in radical form.} \)
4Step 4: Write in Simplified Radical Form
The simplified radical form of \( k^{2/5} \) is \( \sqrt[5]{k^{2}} \), showing the same relation between roots and exponents. Here \( k \) is raised to the power \( 2 \) and then the fifth root is applied.
Key Concepts
Fifth RootExponential FormExponent Properties
Fifth Root
When you first encounter the term "fifth root," it may seem mysterious. However, it is quite straightforward. The fifth root of a number is the value that, when multiplied by itself five times, results in the original number. For example, if we take the fifth root of 32, we are looking for a number that, when raised to the power of five, equals 32. In this case, that number is 2, because 2 raised to the power of 5 (written as \( 2^5 \)) equals 32.
In mathematical notation, a fifth root is expressed as \( \sqrt[5]{x} \). This indicates that the number \( x \) is being operated on by a fifth root, essentially finding a value that satisfies the equation \( x = a^5 \) for some \( a \). Understanding roots, including the fifth root, is crucial for working with both exponents and radicals effectively.
In mathematical notation, a fifth root is expressed as \( \sqrt[5]{x} \). This indicates that the number \( x \) is being operated on by a fifth root, essentially finding a value that satisfies the equation \( x = a^5 \) for some \( a \). Understanding roots, including the fifth root, is crucial for working with both exponents and radicals effectively.
Exponential Form
Exponential form is a concise way of expressing numbers using powers or exponents. It involves expressing a radical expression as a power of a base number. In our exercise, the expression \( \sqrt[5]{k^2} \) can also be written in exponential form. This means expressing the radical as \( (k^2)^{1/5} \).
Understanding how to convert from a radical to an exponential form is essential because it often simplifies calculations. In the expression \( (k^2)^{1/5} \):
Understanding how to convert from a radical to an exponential form is essential because it often simplifies calculations. In the expression \( (k^2)^{1/5} \):
- The base is \( k \).
- The exponent is \( \frac{1}{5} \), indicating the fifth root.
Exponent Properties
Understanding exponent properties can make working with exponents more accessible and manageable. These properties allow us to simplify and manipulate expressions efficiently. Consider the expression \( (k^2)^{1/5} \). To simplify it, we apply the exponent property \((a^m)^n = a^{m \cdot n}\).
For our expression:
For our expression:
- \( m = 2 \) and \( n = \frac{1}{5} \).
- Multiply these values to get the new exponent: \( 2 \times \frac{1}{5} = \frac{2}{5} \).
Other exercises in this chapter
Problem 12
Write each rational expression in lowest terms. $$\frac{20 r+10}{30 r+15}$$
View solution Problem 12
Simplify each expression. Leave answers with exponents. $$\left(\frac{r^{8}}{s^{2}}\right)^{3}$$
View solution Problem 13
Simplify each expression. Assume that all variables represent positive real numbers. $$-4^{1 / 2}$$
View solution Problem 13
Factor each polynomial by grouping. $$6 s t+9 t-10 s-15$$
View solution