Problem 13
Question
Write a general variation equation using \(k\) as the constant of variation. \(T\) varies inversely as the square of \(c\)
Step-by-Step Solution
Verified Answer
The general variation equation for the given relationship is \(T = \frac{k}{c^2}\), where \(T\) varies inversely as the square of \(c\), and \(k\) is the constant of variation.
1Step 1: Define the inverse variation relationship
Since T varies inversely as the square of c, we can write this relationship as follows:
\(T = \frac{k}{c^2}\)
Here, k is the constant of variation.
2Step 2: Write the general variation equation
Now, we have the general variation equation involving T, c, and the constant of variation k:
\(T = \frac{k}{c^2}\)
Key Concepts
General Variation EquationConstant of VariationAlgebraic Relationships
General Variation Equation
When we talk about a general variation equation in algebra, we're discussing how one variable changes concerning another. Variations can be direct or inverse. For instance, in direct variation, if one variable increases, the other also increases. Conversely, inverse variation means if one variable increases, the other decreases.
In the provided exercise, we see a classic example of inverse variation where the variable \( T \) varies inversely as the square of \( c \). The general equation for this kind of variation is given by:
In the provided exercise, we see a classic example of inverse variation where the variable \( T \) varies inversely as the square of \( c \). The general equation for this kind of variation is given by:
- \( T = \frac{k}{c^2} \)
Constant of Variation
The constant of variation, denoted by \( k \), plays a crucial role in any variation equation. It acts as the fixed value that relates two variables, signifying the relationship between them remains consistent.
In our equation, \( T = \frac{k}{c^2} \), the constant \( k \) allows us to understand how changes in \( c \) affect \( T \). No matter what values \( c \) might take, the product \( T \, c^2 \) will always equal \( k \).
In our equation, \( T = \frac{k}{c^2} \), the constant \( k \) allows us to understand how changes in \( c \) affect \( T \). No matter what values \( c \) might take, the product \( T \, c^2 \) will always equal \( k \).
- The constant of variation is essential as it provides a means to calculate unknown quantities given known ones.
- It also tells us something about the initial relationship between the variables \( T \) and \( c \).
Algebraic Relationships
Algebraic relationships involve the connection between variables using equations. These relationships help us describe and predict how one variable behaves as another changes.
In the context of inverse variation, like in our exercise, algebraic relationships are formed by expressing one variable as inversely proportional to another. Algebra operates under universal rules, providing consistency in how equations such as:
In the context of inverse variation, like in our exercise, algebraic relationships are formed by expressing one variable as inversely proportional to another. Algebra operates under universal rules, providing consistency in how equations such as:
- \( T = \frac{k}{c^2} \)
- Predict the behavior of \( T \) for different values of \( c \).
- Formulate strategies for similar problems by identifying patterns in variable interactions.
Other exercises in this chapter
Problem 13
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