Problem 13
Question
Using the Law of Cosines, use the Law of Cosines to solve the triangle. Round your answers to two decimal places. $$ a=11, \quad b=15, \quad c=21 $$
Step-by-Step Solution
Verified Answer
The solutions are \(A = \cos^{-1}(\frac{{15^2 + 21^2 - 11^2}}{{2*15*21}})\), \(B = \cos^{-1}(\frac{{11^2 + 21^2 - 15^2}}{{2*11*21}})\), and \(C = 180 - A - B\). Each of these are rounded to two decimal places.
1Step 1: Calculate Angle A
Use the law of Cosines to solve for angle A. The formula for angle A, \(\cos(A) = \frac{{b^2 + c^2 - a^2}}{{2bc}}\), becomes \(\cos(A) = \frac{{15^2 + 21^2 - 11^2}}{{2*15*21}}\)
2Step 2: Find the Actual Angle A
Use the inverse cosine function to find the actual angle A in degrees: \(A = \cos^{-1}(\frac{{15^2 + 21^2 - 11^2}}{{2*15*21}})\)
3Step 3: Calculate Angle B
Apply the law of Cosines to solve for angle B. The formula for angle B, \(\cos(B) = \frac{{a^2 + c^2 - b^2}}{{2ac}}\), becomes \(\cos(B) = \frac{{11^2 + 21^2 - 15^2}}{{2*11*21}}\)
4Step 4: Find the Actual Angle B
Use the inverse cosine function to find the actual angle B in degrees: \(B = \cos^{-1}(\frac{{11^2 + 21^2 - 15^2}}{{2*11*21}})\)
5Step 5: Use the Triangle Sum Property
Now that we have two angles, we can find the third by using the Triangle Sum Property. It states that the sum of the angles in a triangle is 180 degrees: \(C = 180 - A - B\)
6Step 6: Round your answers
Round each of your final answers to two decimal places
Key Concepts
Triangle Sum PropertyCosine RuleInverse Cosine Function
Triangle Sum Property
The Triangle Sum Property is a fundamental rule in geometry. This property states that the sum of the interior angles of any triangle is always 180 degrees. This knowledge is useful for solving a triangle when two angles are known.
Suppose you have a triangle with angles A, B, and C. According to the Triangle Sum Property:
Suppose you have a triangle with angles A, B, and C. According to the Triangle Sum Property:
- Angle A + Angle B + Angle C = 180°
- Angle C = 180° - (Angle A + Angle B)
Cosine Rule
The Cosine Rule, also known as the Law of Cosines, is an essential tool for solving triangles, especially non-right angled ones. It allows you to calculate an unknown side or angle when you know a little bit about the other parts of the triangle.
The formula for the cosine of angle A is:
The formula for the cosine of angle A is:
- \( \cos(A) = \frac{{b^2 + c^2 - a^2}}{{2bc}} \)
- \( \cos(B) = \frac{{a^2 + c^2 - b^2}}{{2ac}} \)
- \( \cos(C) = \frac{{a^2 + b^2 - c^2}}{{2ab}} \)
Inverse Cosine Function
The inverse cosine function helps you find the angle when you have the cosine of that angle. In trigonometry, the inverse cosine function is denoted as \( \cos^{-1} \). This function will return the angle whose cosine is the given number.
For example, if you know \( \cos(A) = x \), then:
When using trigonometric functions on a calculator, make sure it is set to the correct mode (degrees or radians) to obtain the correct measure of the angle. The inverse cosine function is foundational for converting side-based calculations into angles, thereby completing the puzzle of a triangle's dimensions.
For example, if you know \( \cos(A) = x \), then:
- \( A = \cos^{-1}(x) \)
When using trigonometric functions on a calculator, make sure it is set to the correct mode (degrees or radians) to obtain the correct measure of the angle. The inverse cosine function is foundational for converting side-based calculations into angles, thereby completing the puzzle of a triangle's dimensions.
Other exercises in this chapter
Problem 13
In Exercises \(7-14,\) find \(\mathbf{u} \cdot \mathbf{v}\) $$\mathbf{u}=3 \mathbf{i}+2 \mathbf{j}$$ $$\mathbf{v}=-2 \mathbf{i}-3 \mathbf{j}$$
View solution Problem 13
Trigonometric Form of a Complex Number \(\mathrm{In}\) Exercises \(11-30\) , represent the complex number graphically. Then write the trigonometric form of the
View solution Problem 13
Using the Law of Sines. Use the Law of Sines to solve the triangle. Round your answers to two decimal places. $$A=35^{\circ}, \quad B=65^{\circ}, \quad c=10$$
View solution Problem 14
In Exercises \(7-14,\) find \(\mathbf{u} \cdot \mathbf{v}\) $$\mathbf{u}=\mathbf{i}-2 \mathbf{j}$$ $$\mathbf{v}=-2 \mathbf{i}+\mathbf{j}$$
View solution