Problem 13
Question
Use the variable \(u\) for the inside function to express eac of the following as a composite function: (a) \(y=2^{3 x-1}\) (b) \(P=\sqrt{5 t^{2}+10}\) (c) \(w=2 \ln (3 r+4)\)
Step-by-Step Solution
Verified Answer
(a) \(y = 2^u\), \(u = 3x - 1\); (b) \(P = \sqrt{u}\), \(u = 5t^2 + 10\); (c) \(w = 2\ln(u)\), \(u = 3r + 4\).
1Step 1: Identify the Outside Function for Part (a)
For the expression \(y = 2^{3x-1}\), the outside function is the exponential function. We can set it as \(f(u) = 2^u\).
2Step 2: Identify the Inside Function for Part (a)
The inside function, which will be represented by \(u\), is \(u = 3x - 1\). The composite function is \(y = f(u) = 2^u\).
3Step 3: Express as a Composite Function for Part (a)
Combine the outside and inside functions: \(y = 2^{3x-1}\) is expressed as \(y = f(u) = 2^u\) where \(u = 3x - 1\).
4Step 4: Identify the Outside Function for Part (b)
For the expression \(P = \sqrt{5t^2 + 10}\), the outside function is the square root function. We can set it as \(g(u) = \sqrt{u}\).
5Step 5: Identify the Inside Function for Part (b)
The inside function is \(u = 5t^2 + 10\). The composite function is \(P = g(u) = \sqrt{u}\).
6Step 6: Express as a Composite Function for Part (b)
Combine the outside and inside functions: \(P = \sqrt{5t^2 + 10}\) is expressed as \(P = g(u) = \sqrt{u}\) where \(u = 5t^2 + 10\).
7Step 7: Identify the Outside Function for Part (c)
For the expression \(w = 2 \ln(3r + 4)\), the outside function is the multiplication by 2 and the natural logarithm function. We can set it as \(h(u) = 2\ln(u)\).
8Step 8: Identify the Inside Function for Part (c)
The inside function is \(u = 3r + 4\). The composite function is \(w = h(u) = 2\ln(u)\).
9Step 9: Express as a Composite Function for Part (c)
Combine the outside and inside functions: \(w = 2 \ln(3r + 4)\) is expressed as \(w = h(u) = 2\ln(u)\) where \(u = 3r + 4\).
Key Concepts
Exponential FunctionsSquare Root FunctionsNatural Logarithms
Exponential Functions
Exponential functions are fundamental in algebra and calculus. They involve expressions where a constant base is raised to a variable exponent. A common base for exponential functions is the number 2, as in the expression \( y = 2^{3x-1} \). In this form, replacing the expression \(3x-1\) with a single variable like \(u\) simplifies the function. Thus, we have \( f(u) = 2^u \). In this way, you see that transformations on the exponent can be imagined as separate manipulations within this simplified function.
- **Positive exponents** increase the value as the exponent grows larger.
- **Negative exponents** result in fractional numbers, indicating division.
Square Root Functions
Square root functions are represented mathematically as \( \sqrt{\text{expression}} \). They are the inverse of squaring functions. For example, in the equation \( P = \sqrt{5t^2 + 10} \), the square root is applied to the expression inside the radical, \(5t^2 + 10 \). By introducing the composite function concept, we set \(g(u) = \sqrt{u}\), and this expression inside the root \(5t^2 + 10\) becomes the inside function \(u\).
- **Square roots** are only defined for non-negative numbers in the real number system.
- **Graphs of square root functions** curve upwards in a gentle arc, starting from the origin point \((0, 0)\) when expressed simply as \(y = \sqrt{x}\).
Natural Logarithms
Natural logarithms are represented with the ln notation and come into play when dealing with logarithmic functions, particularly in continuous compounding scenarios. For example, \( w = 2 \ln(3r + 4) \) involves the logarithm of \(3r + 4\) multiplied by 2. In composite terms, this translates to \(h(u) = 2\ln(u)\) with \(u = 3r + 4\) representing the expression inside the logarithm.
- **Natural logarithms** are the inverse operations of exponential functions with base \(e\).
- **The constant \(e\)** is approximately \(2.718\) and is a fundamental constant similar to \(\pi\).
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