Problem 13
Question
Use the given pair of functions to find and simplify expressions for the following functions and state the domain of each using interval notation. $$\bullet (g \circ f)(x)$$ $$\bullet (f \circ g)(x)$$ $$\bullet (f \circ f)(x)$$ $$f(x)=2 x+3, g(x)=x^{2}-9$$
Step-by-Step Solution
Verified Answer
(g ◦ f)(x) = 4x^2 + 12x, (f ◦ g)(x) = 2x^2 - 15, (f ◦ f)(x) = 4x + 9; all domains: (-∞, ∞).
1Step 1: Compose f and g (g ◦ f)(x)
To find \((g \circ f)(x)\), substitute \(f(x) = 2x + 3\) into \(g(x)\). So, compute \(g(f(x)) = g(2x+3)\). Since \(g(x) = x^2 - 9\), substitute to get, \(g(2x+3) = (2x+3)^2 - 9\). Thus, expand this as: \((2x+3)^2 = 4x^2 + 12x + 9\), \(g(f(x)) = 4x^2 + 12x + 9 - 9\). Simplify to\((g \circ f)(x) = 4x^2 + 12x\). Domain: Since \(f(x)\) is a linear function and \(g(x)\) is a polynomial, the domain is all real numbers: \((-\infty, \infty)\).
2Step 2: Compose g and f (f ◦ g)(x)
To find \((f \circ g)(x)\), substitute \(g(x) = x^2 - 9\) into \(f(x)\). So, compute \(f(g(x)) = f(x^2 - 9)\). Since \(f(x) = 2x + 3\), substitute to get: \(f(x^2 - 9) = 2(x^2 - 9) + 3\). Distribute to get: \(2x^2 - 18 + 3\). Simplify to \((f \circ g)(x) = 2x^2 - 15\). Domain: As \(g(x)\) and \(f(x)\) are both polynomials, the domain is all real numbers: \((-\infty, \infty)\).
3Step 3: Compose f with f (f ◦ f)(x)
To find \((f \circ f)(x)\), substitute \(f(x) = 2x + 3\) into \(f(x)\) again. So, compute \(f(f(x)) = f(2x+3)\). Since \(f(x) = 2x + 3\), substitute to get: \(f(2x+3) = 2(2x+3) + 3\). Distribute and simplify to get: \(4x + 6 + 3\). Which simplifies to: \((f \circ f)(x) = 4x + 9\). Domain: The domain of a linear function remains all real numbers, so the domain is \((-\infty, \infty)\).
Key Concepts
Domain of a FunctionPolynomial FunctionsLinear Functions
Domain of a Function
Understanding the domain of a function is crucial for analyzing mathematical expressions. The domain essentially tells us all the possible input values (also known as the independent variable) for which the function exists.
For most polynomial and linear functions, the domain includes all real numbers. This is generally denoted in interval notation as
For most polynomial and linear functions, the domain includes all real numbers. This is generally denoted in interval notation as
- each number from minus infinity to positive infinity is included: \((-\infty, \infty)\).
- Polynomials are continuous, making them defined for any real number,while linear functions also slant without interruptions.
Polynomial Functions
Polynomial functions are expressions involving variables raised to whole number exponents with coefficients. They form the backbone of much algebra and can range from very simple to highly complex forms.
Here's a look at some essential features:
Here's a look at some essential features:
- They consist of terms added together, each term being a product of a constant and a variable raised to a power.
- The general structure is \(a_nx^n + a_{n-1}x^{n-1} + \ldots + a_1x + a_0\), where \(n\) is a non-negative integer.
- The highest power of the variable indicates the polynomial's degree,which informs us about the general shape and the number of turns in the graph.
Linear Functions
Linear functions are one of the foundational building blocks in algebra. They represent the simplest form of relationships between two variables and are characterized by their constant rate of change, also known as the slope.
Key characteristics include:
Key characteristics include:
- The general form of a linear function is \(f(x) = mx + b\), where \(m\) represents the slope, and \(b\) is the y-intercept.
- The graph of a linear function is a straight line, making them easy to recognize and work with.
- They exhibit a uniform level of change.
Other exercises in this chapter
Problem 12
Use the given pair of functions to find the following values if they exist. $$\bullet (g \circ f)(0)$$ $$\bullet (f \circ g)(-1)$$ $$\bullet (f \circ f)(2)$$ $$
View solution Problem 13
Show that the given function is one-to-one and find its inverse. Check your answers algebraically and graphically. Verify that the range of \(f\) is the domain
View solution Problem 14
Show that the given function is one-to-one and find its inverse. Check your answers algebraically and graphically. Verify that the range of \(f\) is the domain
View solution Problem 14
Use the given pair of functions to find and simplify expressions for the following functions and state the domain of each using interval notation. $$\bullet (g
View solution