Problem 13
Question
Use identities to find the exact value of each expression. Do not use a calculator. $$\tan 105^{\circ}$$
Step-by-Step Solution
Verified Answer
The exact value of \( \tan 105^{\circ} \) is \(-2 - \sqrt{3}\).
1Step 1: Identify Known Angles
Recognize that 105° can be expressed as a sum of angles where the tangent values are known. Notice that 105° = 60° + 45°.
2Step 2: Use Tangent Addition Formula
Use the tangent addition formula: \( \tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \cdot \tan B} \). Apply it to \( A = 60^{\circ} \) and \( B = 45^{\circ} \).
3Step 3: Find Tangent Values for Known Angles
Find \( \tan 60^{\circ} = \sqrt{3} \) and \( \tan 45^{\circ} = 1 \).
4Step 4: Substitute Known Values into the Formula
Substitute the values back into the formula: \( \tan 105^{\circ} = \frac{\sqrt{3} + 1}{1 - \sqrt{3} \cdot 1} \).
5Step 5: Simplify the Expression
Simplify the expression: \( \tan 105^{\circ} = \frac{\sqrt{3} + 1}{1 - \sqrt{3}} = \frac{\sqrt{3} + 1}{-\sqrt{3} + 1} \).
6Step 6: Rationalize the Denominator
To rationalize, multiply numerator and denominator by \( \sqrt{3} + 1 \): \( \tan 105^{\circ} = \frac{(\sqrt{3} + 1)^2}{(\sqrt{3} - 1)(\sqrt{3} + 1)} \).
7Step 7: Simplify Further
Calculate \( (\sqrt{3} + 1)^2 = 3 + 2\sqrt{3} + 1 = 4 + 2\sqrt{3} \) and \( (\sqrt{3} - 1)(\sqrt{3} + 1) = 3 - 1 = 2 \).
8Step 8: Final Simplification
Finally, divide \( 4 + 2\sqrt{3} \) by 2, resulting in \( 2 + \sqrt{3} \). Thus, \( \tan 105^{\circ} = -2 - \sqrt{3} \).
Key Concepts
Angle Addition FormulaTrigonometric IdentitiesRationalizing Denominators
Angle Addition Formula
The angle addition formula is a crucial tool in trigonometry, allowing us to find the tangent of a sum of two angles using known values. This formula for tangent is represented as the following:
\[ \tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \cdot \tan B} \]
This approach not only simplifies finding values but also reinforces understanding of how trigonometric identities link different angles together.
\[ \tan(A + B) = \frac{\tan A + \tan B}{1 - \tan A \cdot \tan B} \]
- Imagine you're dealing with angles like 105°, 135°, or others that aren't standard on the unit circle.
- Breaking these angles into a sum of known angles, like 60° and 45°, helps you find the tangent.
- This strategy works because angles like 60° and 45° have easy-to-remember tangent values.
This approach not only simplifies finding values but also reinforces understanding of how trigonometric identities link different angles together.
Trigonometric Identities
Trigonometric identities are equations that relate the angles and various trigonometric functions. They are pivotal in simplifying and solving trigonometric expressions. Knowing these identities and how to apply them can make complex problems more manageable.
Some key trigonometric identities are:
Some key trigonometric identities are:
- Pythagorean Identities: such as \( \sin^2\theta + \cos^2\theta = 1 \)
- Reciprocal Identities: \( \tan\theta = \frac{\sin\theta}{\cos\theta} \)
- Angle Sum and Difference Identities: \( \sin(A \pm B), \cos(A \pm B), \tan(A \pm B) \)
Rationalizing Denominators
Rationalizing the denominator is a technique used to eliminate radicals, such as square roots, from the denominator of a fraction. This process makes expressions easier to handle and is often required for final results in mathematics.
Here's how to rationalize a denominator:
Here's how to rationalize a denominator:
- If you have a denominator like \( \sqrt{3} - 1 \), multiply both the numerator and the denominator by its conjugate, \( \sqrt{3} + 1 \).
- For example, in the expression \( \frac{\sqrt{3} + 1}{1 - \sqrt{3}} \), you multiply by \( \frac{\sqrt{3} + 1}{\sqrt{3} + 1} \).
- This brings the denominator to a simpler form, such as 2, eliminating the square root.
Other exercises in this chapter
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