Problem 13
Question
The first four terms of a sequence are given. Determine whether these terms can be the terms of a geometric sequence. If the sequence is geometric, find the common ratio. $$3,6,12,24, \dots$$
Step-by-Step Solution
Verified Answer
The sequence is geometric with a common ratio of 2.
1Step 1: Definition of a Geometric Sequence
A geometric sequence is a sequence of numbers where each term after the first is found by multiplying the previous term by a fixed, non-zero number called the common ratio, denoted as \(r\).
2Step 2: Determine Ratios Between Consecutive Terms
To check whether the sequence \(3, 6, 12, 24, \dots\) is geometric, compute the ratio between consecutive terms: \(\frac{6}{3} = 2\), \(\frac{12}{6} = 2\), and \(\frac{24}{12} = 2\).
3Step 3: Conclusion of Common Ratio
Since the ratio between each pair of consecutive terms is the same (\(r = 2\)), the sequence is indeed geometric.
4Step 4: Identify the Common Ratio
The common ratio \(r\) of this geometric sequence is \(2\). Each term is obtained by multiplying the previous term by \(2\).
Key Concepts
Understanding the Common RatioSequence of Numbers in Geometric ProgressionMultiplying Terms in a Geometric Sequence
Understanding the Common Ratio
In a geometric sequence, the common ratio is pivotal. It is the fixed number that you multiply with one term to get the next term in the sequence. This is essentially the heart of how a geometric sequence is formed. For the sequence to be geometric, this ratio must be consistent across all pairs of consecutive terms.
For example, in the sequence given: 3, 6, 12, 24, we calculated the common ratio by dividing each term by its preceding term. Thus,
Whenever you encounter a sequence you suspect might be geometric, checking the common ratio is your go-to strategy. It is this consistent multiplication factor that verifies the sequence's geometric nature.
For example, in the sequence given: 3, 6, 12, 24, we calculated the common ratio by dividing each term by its preceding term. Thus,
- \(\frac{6}{3} = 2\)
- \(\frac{12}{6} = 2\)
- \(\frac{24}{12} = 2\)
Whenever you encounter a sequence you suspect might be geometric, checking the common ratio is your go-to strategy. It is this consistent multiplication factor that verifies the sequence's geometric nature.
Sequence of Numbers in Geometric Progression
A geometric sequence is simply a sequence of numbers where each term after the first is determined by multiplying the previous one by a constant number. This type of sequence is different from an arithmetic sequence, where you add a constant value. Instead, you're repeatedly multiplying by the common ratio.
In the sequence we've been exploring (3, 6, 12, 24), each number multiplies to the next by \(2\).
By understanding how each number follows the previous in this chain of multiplication, you grasp the essence of a geometric sequence.
In the sequence we've been exploring (3, 6, 12, 24), each number multiplies to the next by \(2\).
- Start with 3
- Multiply by 2 to get the next term: 6
- Multiply by 2 again: 12
- Once more by 2: 24
By understanding how each number follows the previous in this chain of multiplication, you grasp the essence of a geometric sequence.
Multiplying Terms in a Geometric Sequence
When dealing with a geometric sequence, multiplying terms is your core operation. Once you've identified the common ratio, you can generate any term in the sequence by multiplying the preceding term by this ratio.
For the sequence 3, 6, 12, 24, we've already determined that the common ratio is 2.
Understanding this multiplication process allows you to extend the sequence infinitely or find any specific term based on its position.
For the sequence 3, 6, 12, 24, we've already determined that the common ratio is 2.
- Starting from the first term, 3: multiply by 2 to get 6
- From 6: multiply by 2 to get 12
- From 12: multiply by 2 to reach 24
Understanding this multiplication process allows you to extend the sequence infinitely or find any specific term based on its position.
Other exercises in this chapter
Problem 13
Find the \(n\) th term of the arithmetic sequence with given first term \(a\) and common difference \(d .\) What is the 10 th term? $$a=-0.7, \quad d=-0.2$$
View solution Problem 13
Funding an Annuity How much money must be invested now at \(9 \%\) per year, compounded semiannually, to fund an annuity of 20 payments of \(\$ 200\) each, paid
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Pascal's Triangle Use Pascal's triangle to expand the expression. $$(2 x-3 y)^{3}$$
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Use mathematical induction to prove that the formula is true for all natural numbers \(n\) $$\begin{aligned} 1 \cdot 2+2 \cdot 2^{2}+3 \cdot 2^{3}+4 \cdot 2^{4}
View solution