Problem 13
Question
$$\text { Find } f^{\prime}(x)$$ $$f(x)=x^{e}+\frac{1}{x^{\sqrt{10}}}$$
Step-by-Step Solution
Verified Answer
\(f'(x) = e \, x^{e-1} - \sqrt{10} \, x^{-\sqrt{10}-1}\)
1Step 1: Differentiate the first term
To differentiate the function, start by finding the derivative of the first term, which is \(x^{e}\). According to the power rule, the derivative of \(x^a\) is \(a \, x^{a-1}\). Here, \(a = e\), so the derivative is \(e \, x^{e-1}\).
2Step 2: Differentiate the second term
Next, find the derivative of the second term, \(\frac{1}{x^{\sqrt{10}}}\). Rewrite this as \(x^{-\sqrt{10}}\). Again, apply the power rule. The derivative is \(-\sqrt{10} \, x^{-\sqrt{10}-1}\).
3Step 3: Combine the derivatives
Now that we have the derivatives of both terms, combine them to find the overall derivative of the function. The derivative of \(f(x)\) is \(f'(x) = e \, x^{e-1} - \sqrt{10} \, x^{-\sqrt{10}-1}\).
Key Concepts
Power RuleDerivative of PolynomialsExponential Functions
Power Rule
The power rule is a fundamental concept in calculus, especially when it comes to differentiation. It's a straightforward method used to calculate the derivative of power functions, which are expressions of the form \(x^n\), where \(n\) is any real number.
The power rule states that if you have a function \(f(x) = x^n\), then its derivative \(f'(x)\) is given by bringing down the exponent as a coefficient and reducing the exponent by one, which results in \(n \, x^{n-1}\).
The power rule states that if you have a function \(f(x) = x^n\), then its derivative \(f'(x)\) is given by bringing down the exponent as a coefficient and reducing the exponent by one, which results in \(n \, x^{n-1}\).
- For example, to differentiate \(x^3\), you apply the rule to get the derivative \(3 \, x^{2}\).
- This principle also applies to non-integer exponents like \(e\), as seen in our problem, where \(f(x) = x^e\) leads to \(f'(x) = e \, x^{e-1}\).
Derivative of Polynomials
In calculus, a polynomial is a mathematical expression that consists of variables raised to whole number exponents and constant coefficients. Polynomial expressions can range from simple monomials to complex combinations of terms.
The derivative of a polynomial function is found by differentiating each term individually. Thanks to the linearity of differentiation, each term can be handled separately and then summed up to form the final derivative.
The derivative of a polynomial function is found by differentiating each term individually. Thanks to the linearity of differentiation, each term can be handled separately and then summed up to form the final derivative.
- Take, for example, \(f(x) = 3x^2 + 4x + 5\). The derivative, \(f'(x)\), is the sum of the derivatives of each term: \(6x + 4\).
- The process involves applying the power rule to each term where the exponent is a positive integer.
Exponential Functions
Exponential functions are characterized by a constant base raised to a variable exponent. These functions exhibit rapid growth or decay. However, when differentiating exponential functions with a variable in the exponent, additional rules apply beyond the basic power rule.
In scenarios involving expressions such as \(f(x) = a^{x}\), where \(a\) is a positive constant, the derivative is found using principles of natural logarithms. However, when the base of an exponential function is the mathematical constant \(e\), the differentiation process simplifies greatly because \(e^x\) differentiates to \(e^x\).
In scenarios involving expressions such as \(f(x) = a^{x}\), where \(a\) is a positive constant, the derivative is found using principles of natural logarithms. However, when the base of an exponential function is the mathematical constant \(e\), the differentiation process simplifies greatly because \(e^x\) differentiates to \(e^x\).
- In our initial problem, we encounter the expression \(x^e\) where \(x\) is the base, and \(e\) is the exponent. Since the exponent is constant, the power rule works effectively here.
- If the scenario involved \(e^x\), the persistent rate of change means its derivative is itself: \(e^x\).
Other exercises in this chapter
Problem 13
A function \(y=f(x)\) and values of \(x_{0}\) and \(x_{1}\) are given. (a) Find the average rate of change of \(y\) with respect to \(x\) over the interval \(\l
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