Problem 13
Question
Suppose that \(A\) and \(B\) are \(4 \times 4\) invertible matrices. If \(\operatorname{det}(A)=-2\) and \(\operatorname{det}(B)=3,\) compute each determinant below. $$\operatorname{det}\left((-A)^{3}\left(2 B^{2}\right)\right)$$.
Step-by-Step Solution
Verified Answer
The short answer to the question based on the given step-by-step solution is:
The determinant of \((-A)^3(2B^2)\) is \(-18432\).
1Step 1: Understanding properties of determinants
Recall the following properties of determinants:
1. \(\operatorname{det}(AB) = \operatorname{det}(A) \operatorname{det}(B)\)
2. \(\operatorname{det}(kA) = k^n \operatorname{det}(A)\) for an \(n \times n\) matrix \(A\) and scalar \(k\)
3. \(\operatorname{det}(A^k) = (\operatorname{det}(A))^k\) for an \(n \times n\) matrix \(A\)
2Step 2: Applying the properties to the given expression
We have to compute \(\operatorname{det}\left((-A)^{3}\left(2 B^{2}\right)\right)\). Using the properties of determinants, we can rewrite this expression as:
\[
\operatorname{det}\left((-A)^{3}\right) \operatorname{det}\left(2 B^{2}\right)
\]
Now, apply the properties again to simplify the expression further:
\[
(-1)^{3 \times 4} \operatorname{det}\left(A^{3}\right) \cdot 2^{2 \times 4} \operatorname{det}\left((B^{2})\right)
\]
3Step 3: Compute the final determinant
Now, use the given values of \(\operatorname{det}(A)\) and \(\operatorname{det}(B)\) and the property \(\operatorname{det}(A^k) = (\operatorname{det}(A))^k\):
\[
(-1)^{12} (-2)^{3} \cdot 2^{8} (3)^{2}
\]
This simplifies to:
\[
(1)(-8)(256)(9)
\]
Multiplying these values, we get:
\[
\operatorname{det}\left((-A)^{3}\left(2 B^{2}\right)\right) = -18432
\]
So, the determinant of the given expression is -18432.
Key Concepts
Matrix MultiplicationScalar Multiplication in MatricesInvertible MatricesMatrix Powers
Matrix Multiplication
Matrix multiplication is a fundamental operation in linear algebra. It combines two matrices to form a new matrix. If you have two matrices, say matrix \(A\) of size \(m \times n\) and matrix \(B\) of size \(n \times p\), they can be multiplied together only if the number of columns in \(A\) matches the number of rows in \(B\). The result is a new matrix \(C\) of size \(m \times p\).
- The elements of the resulting matrix \(C\) are calculated by taking the dot product of rows from \(A\) and columns from \(B\).
- Matrix multiplication is not commutative, which means \(AB eq BA\) in general.
Scalar Multiplication in Matrices
Scalar multiplication involves multiplying each entry of a matrix by a constant value, called a scalar. If matrix \(A\) is given and scalar \(k\) is a real number, the product \(kA\) is another matrix where each element \(a_{ij}\) of \(A\) is multiplied by \(k\).
- This operation scales the matrix by the scalar value and can alter both the size and direction of a vector contained within a matrix.
- When used in the context of determinants, scalar multiplication affects the determinant of the matrix by multiplying it by \(k^n\), where \(n\) is the size (number of rows or columns) of the square matrix.
Invertible Matrices
An invertible matrix, also known as a non-singular or non-degenerate matrix, is a square matrix that possesses an inverse. If matrix \(A\) has an inverse, it is denoted as \(A^{-1}\), and it satisfies the condition \(AA^{-1} = A^{-1}A = I\), where \(I\) is the identity matrix.
- The determinant of an invertible matrix is non-zero. This property is crucial, as having a zero determinant implies that the matrix is singular and does not have an inverse.
- Invertible matrices are essential in solving systems of linear equations, and they ensure that transformations are reversible.
- In the context of determinant properties, knowing that matrices are invertible can simplify complex determinant calculations by confirming that inverses exist.
Matrix Powers
When we talk about matrix powers, we mean raising a matrix to a certain exponent, similar to how we raise numbers to powers. Specifically, for a square matrix \(A\), the \(k\)-th power of \(A\) is denoted as \(A^k\), and it involves multiplying the matrix \(A\) by itself \(k\) times.
- Matrix powers only make sense for square matrices since multiplication of non-square matrices would result in inconsistent dimensions.
- For determinants, the property \(\operatorname{det}(A^k) = (\operatorname{det}(A))^k\) helps in simplifying computations concerning matrix powers.
- Matrix powers can be used to compute state transitions in Markov chains, solve differential equations, and model repetitive transformations.
Other exercises in this chapter
Problem 12
Determine the values of the indices \(p\) and \(q\) such that the following are terms in a determinant of order \(4 .\) In each case, determine the number of in
View solution Problem 12
Evaluate the determinant of the given matrix by first using elementary row operations to reduce it to upper triangular form. $$\left|\begin{array}{rrrr} 7 & -1
View solution Problem 13
Find \(\operatorname{det}(A) .\) If \(A\) is invertible, use the adjoint method to find \(A^{-1}\). $$A=\left[\begin{array}{rrrr}5 & -1 & 2 & 1 \\\3 & -1 & 4 &
View solution Problem 13
Use the cofactor expansion theorem to evaluate the given determinant along the specified row or column. \(\left|\begin{array}{rrrr}1 & -2 & 3 & 0 \\ 4 & 0 & 7 &
View solution