Problem 13
Question
State conditions on \(a\) and \(b\) that guarantee that the matrix \(\left[\begin{array}{ll}a & 0 \\ 0 & b\end{array}\right]\) has an inverse, and find a formula for the inverse if it exists.
Step-by-Step Solution
Verified Answer
The conditions are \(a \neq 0\) and \(b \neq 0\); the inverse is \(\begin{bmatrix} \frac{1}{a} & 0 \\ 0 & \frac{1}{b} \end{bmatrix}\)."
1Step 1: Identify Conditions for Matrix to be Invertible
For a 2x2 diagonal matrix \(\begin{bmatrix} a & 0 \ 0 & b \end{bmatrix}\) to have an inverse, both diagonal elements must be nonzero. This ensures that the determinant of the matrix is nonzero. Specifically, we need \( a eq 0 \) and \( b eq 0 \).
2Step 2: Calculate the Determinant
The determinant of a diagonal matrix \(\begin{bmatrix} a & 0 \ 0 & b \end{bmatrix}\) is calculated as \( \text{det}(A) = a \times b \). The matrix is invertible if and only if the determinant is nonzero. In this case, \( a \cdot b eq 0 \).
3Step 3: Write the Formula for the Inverse
If the matrix is invertible, its inverse can be found by taking the reciprocal of each nonzero diagonal element. Thus, the inverse of the matrix \(\begin{bmatrix} a & 0 \ 0 & b \end{bmatrix}\) is \(\begin{bmatrix} \frac{1}{a} & 0 \ 0 & \frac{1}{b} \end{bmatrix}\).
Key Concepts
Diagonal MatrixDeterminantInvertible MatrixInverse Matrix Formula
Diagonal Matrix
A diagonal matrix is a type of square matrix where all the elements outside the main diagonal are zero. In formal terms, a matrix is diagonal if it is of the form:
- For a 2x2 matrix: \[\begin{bmatrix}a & 0 \0 & b\end{bmatrix}\]
- Here, \(a\) and \(b\) are the diagonal elements.
Determinant
The determinant is a special number calculated from a matrix, giving us essential information. For diagonal matrices, finding the determinant is particularly straightforward. The determinant of a 2x2 diagonal matrix, like the one discussed, is simply the product of its diagonal elements:
- For \[\begin{bmatrix}a & 0 \0 & b\end{bmatrix}\], the determinant is \( ext{det}(A) = a \times b \).
Invertible Matrix
An invertible matrix, also known as a non-singular or non-degenerate matrix, is one that has an inverse. The existence of an inverse matrix is tied directly to the determinant of the matrix.For a diagonal matrix:
- The necessary and sufficient condition for a matrix to be invertible is that its determinant is not zero.
- This means each diagonal element must be non-zero. Specifically for our example: \(a eq 0\) and \(b eq 0\).
Inverse Matrix Formula
Finding the inverse of a diagonal matrix is simpler than other matrices because of its structure. The inverse of a matrix is a matrix such that when multiplied with the original, results in the identity matrix.For a diagonal matrix:
- Given the matrix \[\begin{bmatrix}a & 0 \0 & b\end{bmatrix}\], its inverse is \[\begin{bmatrix}\frac{1}{a} & 0 \0 & \frac{1}{b}\end{bmatrix}\].
- This computation involves taking the reciprocal of each non-zero diagonal element.
Other exercises in this chapter
Problem 12
Solve the system. $$ \left\\{\begin{array}{l} \sqrt{5} x+\sqrt{3} y=14 \sqrt{3} \\ \sqrt{3} x-2 \sqrt{5} y=-2 \sqrt{5} \end{array}\right. $$
View solution Problem 13
Exer. 1-28: Find the partial fraction decomposition. $$ \frac{x^{2}-6}{(x+2)^{2}(2 x-1)} $$
View solution Problem 13
Find, if possible, \(A B\) and \(B A\). $$ A=\left[\begin{array}{rrr} 3 & 0 & -1 \\ 0 & 4 & 2 \\ 5 & -3 & 1 \end{array}\right], \quad B=\left[\begin{array}{rrr}
View solution Problem 13
\(\left\\{\begin{array}{r}x+y-2 z=0 \\ x-y-4 z=0 \\ y+z=0\end{array}\right.\)
View solution