Problem 13
Question
Solve each of the equations. $$ 16^{x}=64 \quad\left\\{\frac{3}{2}\right\\} $$
Step-by-Step Solution
Verified Answer
The solution is \(x = \frac{3}{2}\).
1Step 1: Identify Common Base
First, we notice both numbers, 16 and 64, can be expressed as powers of 2. We know that \(16 = 2^4\) and \(64 = 2^6\). Therefore, we can rewrite the equation.
2Step 2: Rewrite the Equation in Terms of Powers of 2
Rewrite the original equation \(16^x=64\) as \((2^4)^x = 2^6\).
3Step 3: Apply the Power of a Power Rule
Apply the rule \((a^m)^n = a^{m \cdot n}\) to the left side of the equation: \((2^4)^x = 2^{4x}\). The equation now becomes \(2^{4x} = 2^6\).
4Step 4: Equate the Exponents
Since the bases are the same (both are 2), we can equate the exponents: \(4x = 6\).
5Step 5: Solve for x
Divide both sides of the equation by 4 to solve for \(x\): \(x = \frac{6}{4} = \frac{3}{2}\).
Key Concepts
Common Base IdentificationPower of a Power RuleEquating ExponentsSolving Linear Equations
Common Base Identification
Before we can dive into solving exponential equations, it's crucial to understand how identifying a common base can simplify the process. Exponential expressions often involve numbers that can be broken down into powers of smaller, often prime, numbers. For instance, in the equation above — where you have two different bases (16 and 64) — you'll find that both numbers can be expressed as powers of the base number 2.
- 16 can be expressed as \(2^4\).
- 64 can be reflected as \(2^6\).
Power of a Power Rule
When working with exponential expressions, you'll often come across terms nested within each other, such as \((a^m)^n\). This is where the "Power of a Power" rule is immensely useful. This rule states that when you raise a power to another power, you can multiply the exponents.
For example, given an expression \((2^4)^x\), applying the rule transforms it into \(2^{4x}\). This simplification allows us to work directly with the exponents rather than dealing with nested powers.
It's an incredibly handy tool for simplifying equations, especially in tests where time is of the essence.
For example, given an expression \((2^4)^x\), applying the rule transforms it into \(2^{4x}\). This simplification allows us to work directly with the exponents rather than dealing with nested powers.
It's an incredibly handy tool for simplifying equations, especially in tests where time is of the essence.
Equating Exponents
Equating the exponents is a pivotal step when solving exponential equations. Once you have transformed both sides of your equation to have the same base, you can set their exponents equal to each other.
In our example, transforming \(16^x = 64\) gives us \(2^{4x} = 2^6\). Since the base is now the same on both sides, namely the base 2, the exponents must also be equal for the equation to hold true.
In our example, transforming \(16^x = 64\) gives us \(2^{4x} = 2^6\). Since the base is now the same on both sides, namely the base 2, the exponents must also be equal for the equation to hold true.
- Equation becomes \(4x = 6\)
Solving Linear Equations
Having equated the exponents, you're now left with a linear equation, such as \(4x = 6\). Solving linear equations is generally straightforward:
- Use inverse operations to isolate the variable.
- In this case, divide both sides by 4 to get \(x = \frac{6}{4} = \frac{3}{2}\).
Other exercises in this chapter
Problem 13
Determine whether the function \(f\) is one-to-one. $$ f(x)=-x^{4} $$
View solution Problem 13
Use the formula \(A=P\left(1+\frac{r}{n}\right)^{n t}\) to find the total amount of money accumulated at the end of the indicated time period for each of the fo
View solution Problem 14
Solve each exponential equation and express approximate solutions to the nearest hundredth. $$ e^{x-1}=8.2 $$
View solution Problem 14
Use your calculator to find \(x\) when given \(\log x\). Express answers to five significant digits. $$ \log x=3.9335 $$
View solution