Problem 13
Question
Solve each inequality. Write each solution set in interval notation. $$-2 x+8 \leq 16$$
Step-by-Step Solution
Verified Answer
The solution set in interval notation is \([-4, \infty)\).
1Step 1 - Isolate the variable term
First, subtract 8 from both sides of the inequality to isolate the term with the variable. \[ -2x + 8 - 8 \leq 16 - 8 \] This simplifies to: \[ -2x \leq 8 \]
2Step 2 - Solve for the variable
Next, divide both sides of the inequality by -2. Remember, dividing by a negative number reverses the inequality direction: \[ x \geq \frac{8}{-2} \] This simplifies to: \[ x \geq -4 \]
3Step 3 - Write the solution in interval notation
The solution \( x \geq -4 \) means that x can be any number greater than or equal to -4. In interval notation, this is written as: \[ [-4, \infty) \]
Key Concepts
Interval NotationInequality ReversalLinear Inequalities
Interval Notation
When we solve inequalities, writing the solution in interval notation is a clear and standardized way to represent the range of possible values for the variable. Interval notation uses brackets and parentheses to describe these ranges. Here's a quick guide:
- [a, b]: Includes both endpoints a and b (closed interval).
- (a, b]: Excludes the start point a, includes the endpoint b (half-open interval).
- [a, b): Includes the start point a, excludes the endpoint b (half-open interval).
- (a, b): Excludes both endpoints a and b (open interval).
Inequality Reversal
One essential rule to remember when solving inequalities is the effect of multiplying or dividing by a negative number. This action requires reversing the inequality sign. Here’s why: Suppose we have the inequality \[7 > 3\]. Clearly, this is true. But if we multiply both sides by -1, we get: \[-7 > -3\]. This statement is false because -7 is actually less than -3. To correct it, we must reverse the symbol: \[-7 < -3\]. Similarly, when solving \[-2x \leq 8\], we divide both sides by -2, yielding \[x \geq -4\]. Reversing the inequality ensures the truth of the relationship between the quantities remains intact. Always be vigilant about this rule when working with inequalities.
Linear Inequalities
Linear inequalities, such as \[-2x + 8 \leq 16\], involve variables raised to the first power. Solving them is somewhat like solving linear equations, but with one key difference – the possibility of reversing the inequality when multiplying or dividing by negative numbers. Here’s a structured approach to solving them:
- Isolate the variable: Separate the term with the variable from the constants. For the given equation, subtract 8 from both sides: \[-2x + 8 - 8 \leq 16 - 8\], simplifying to \[-2x \leq 8\].
- Solve for the variable: Divide or multiply to get the variable alone. In this case, divide by -2 (and remember to reverse the inequality): \[x \geq -4\].
- Express in interval notation: Translate the inequality to interval form. For \[x \geq -4\], the interval notation is \[[-4, \infty)\].
Other exercises in this chapter
Problem 13
Solve each equation. $$\left|\frac{x-4}{2}\right|=5$$
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Solve each equation. $$\frac{4}{x^{2}+x-6}-\frac{1}{x^{2}-4}=\frac{2}{x^{2}+5 x+6}$$
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Solve each equation. $$\frac{5}{6} x-2 x+\frac{4}{3}=\frac{5}{3}$$
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Solve each equation by the zero-factor property. $$x^{2}-5 x+6=0$$
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