Problem 13
Question
Solve each equation. Check each solution. $$ \frac{3 x-2}{12}-\frac{1}{6}=\frac{1}{6} $$
Step-by-Step Solution
Verified Answer
The solution to the equation is \(x = 4/3\).
1Step 1: Get rid of the fractions
Multiplying every term by 12 (which is the common denominator), we simplify the equation into: \(2(3x - 2) - 2 = 2\)
2Step 2: Distribute and Simplify
Distribute the 2 into the bracket and simplify the like terms:\(6x - 4 - 2 = 2\) which further simplifies to \(6x - 6 = 2\)
3Step 3: Solve for x
To solve for \(x\), first add 6 to both sides of the equation: \(6x = 8\). Dividing both sides of the equation by 6, we find \(x = 8/6\) which simplifies to \(x = 4/3 or 1.33\)
4Step 4: Verify the solution
Substitute \(x = 4/3\) into the original equation.\[\frac{3(4/3)-2}{12}-\frac{1}{6}=\frac{1}{6}\]After simplification, \[\frac{4-2}{12}-\frac{1}{6}=\frac{1}{6}\]This simplifies to:\[\frac{1}{6}-\frac{1}{6}=\frac{1}{6}\]Or \(0 = 0\), which verifies that our solution, \(x = 4/3\), is correct.
Key Concepts
Fractions in EquationsAlgebraic ManipulationVerifying Solutions
Fractions in Equations
When working with equations that contain fractions, it can seem daunting at first. The key is to simplify the equation by eliminating the fractions. This is typically achieved by finding a common denominator for all terms involved. In our exercise, the denominators were simplified by multiplying each term by 12, which is the least common multiple of the denominators 6 and 12. This step is crucial because once the fractions are gone, you are left with a much simpler equation.
For example, consider the equation with fractions:
This process of eliminating fractions not only makes your algebraic manipulations easier but also minimizes potential errors in calculations.
For example, consider the equation with fractions:
- \( \frac{3x - 2}{12} - \frac{1}{6} = \frac{1}{6} \)
This process of eliminating fractions not only makes your algebraic manipulations easier but also minimizes potential errors in calculations.
Algebraic Manipulation
Once you've eliminated fractions from your equation, you're left with a more straightforward algebraic problem. Algebraic manipulation involves rearranging and simplifying the equation to find the solution for the variable.
Taking our example further, after clearing fractions, we had the equation:
Following distribution, you simplify by combining like terms if possible. Here, you subtract 6 from both sides, resulting in a simplified equation: \( 6x = 8 \).
To find \( x \), divide both sides by 6. This brings us to the solution: \( x = \frac{4}{3} \). Effective algebraic manipulation allows you to isolate and solve for your variable with clarity and precision.
Taking our example further, after clearing fractions, we had the equation:
- \( 2(3x - 2) - 2 = 2 \)
Following distribution, you simplify by combining like terms if possible. Here, you subtract 6 from both sides, resulting in a simplified equation: \( 6x = 8 \).
To find \( x \), divide both sides by 6. This brings us to the solution: \( x = \frac{4}{3} \). Effective algebraic manipulation allows you to isolate and solve for your variable with clarity and precision.
Verifying Solutions
Verifying your solution means checking that your value for \( x \) satisfies the original equation. It's a crucial step to ensure there are no errors in your calculations and that your solution is correct.
In this exercise, after finding \( x = \frac{4}{3} \), you return to the original equation:
In this exercise, after finding \( x = \frac{4}{3} \), you return to the original equation:
- \( \frac{3x - 2}{12} - \frac{1}{6} = \frac{1}{6} \)
- \( \frac{3(4/3) - 2}{12} - \frac{1}{6} = \frac{1}{6} \)
Other exercises in this chapter
Problem 12
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