Problem 13
Question
Solve each equation. $$ a^{\frac{1}{2}}+9=0 $$
Step-by-Step Solution
Verified Answer
No real solution.
1Step 1: Isolate the Power Term
To solve the equation, we first isolate the term involving the variable. We have the equation \(a^{\frac{1}{2}} + 9 = 0\). We can isolate the \(a^{\frac{1}{2}}\) by subtracting 9 from both sides: \(a^{\frac{1}{2}} = -9\).
2Step 2: Analyze the Square Root
The expression \(a^{\frac{1}{2}}\) is equivalent to \(\sqrt{a}\). Since the square root of a number must be non-negative, \(\sqrt{a} = -9\) has no real solutions.
Key Concepts
Solving EquationsSquare RootsNo Real Solutions
Solving Equations
Solving equations is a fundamental concept in algebra that involves finding the value of the unknown variable that makes the equation true. We follow a series of logical steps to isolate and solve for the variable. To do this, we often need to manipulate the equation using basic arithmetic operations.
- Isolating the variable: This involves rearranging the equation so that the variable is on one side and the constants are on the other.
- In our example equation, \(a^{\frac{1}{2}} + 9 = 0\), we want to isolate \(a^{\frac{1}{2}}\).
- We achieve this by subtracting 9 from both sides, resulting in \(a^{\frac{1}{2}} = -9\).
Square Roots
Square roots are mathematical operations that "undo" squaring a number. The square root of a number \(a\) is a value \(b\) such that \(b^2 = a\). In our example, when we see \(a^{\frac{1}{2}}\), it is equivalent to \(\sqrt{a}\).
- This notation means we are looking for a number that, when squared, returns the original value \(a\).
- Importantly, the principal square root is always non-negative, as it represents the length or distance.
No Real Solutions
In mathematics, not all equations can be solved in the real numbers. An equation can be said to have "no real solutions" if there is no real number that satisfies it. This occurs because of certain characteristics of operations like square roots.
- For instance, in the equation \(a^{\frac{1}{2}} = -9\), we face such a scenario.
- The square root of a number cannot be negative, as square roots represent lengths which are inherently non-negative.
- Therefore, \(\sqrt{a} = -9\) is impossible, indicating that there are no real solutions to this equation.
Other exercises in this chapter
Problem 12
Graph each function. State the domain and range of each function. \(y=\frac{1}{2} \sqrt{x}\)
View solution Problem 12
Find the inverse of each relation. $$ \\{(7,-4),(3,5),(-1,4),(7,5)\\} $$
View solution Problem 13
Simplify each expression. $$ \sqrt[6]{27 x^{3}} $$
View solution Problem 13
Simplify. \(3 \sqrt[3]{128}+5 \sqrt[3]{16}\)
View solution