Problem 13
Question
Sketch several solution curves in the phase plane of the system of differential equations \(d \mathbf{x} / d t=A \mathbf{x}\) using the given eigenvalues and eigenvectors of \(A .\) \(\lambda_{1}=2, \quad \lambda_{2}=-2 ; \quad \mathbf{v}_{1}=\left[ \begin{array}{l}{3} \\ {1}\end{array}\right] \quad \mathbf{v}_{2}=\left[ \begin{array}{l}{1} \\ {1}\end{array}\right]\)
Step-by-Step Solution
Verified Answer
Sketch trajectories diverging along \( \mathbf{v}_1 \) and converging along \( \mathbf{v}_2 \); origin is a saddle point.
1Step 1: Understand the System Dynamics
The system is given by \( \frac{d \mathbf{x}}{dt} = A \mathbf{x} \) where \( A \) is a matrix. The eigenvalues \( \lambda_1 = 2 \) and \( \lambda_2 = -2 \) tell us that we have solutions that behave exponentially. A positive eigenvalue \( \lambda_1 = 2 \) means solutions grow exponentially in the direction of \( \mathbf{v}_1 \), and a negative eigenvalue \( \lambda_2 = -2 \) means solutions decay exponentially in the direction of \( \mathbf{v}_2 \).
2Step 2: Identify Solution Behavior
With \( \lambda_1 = 2 \) and the eigenvector \( \mathbf{v}_1 = \begin{bmatrix} 3 \ 1 \end{bmatrix} \), solutions will move away from the origin along this vector. With \( \lambda_2 = -2 \) and eigenvector \( \mathbf{v}_2 = \begin{bmatrix} 1 \ 1 \end{bmatrix} \), solutions will move towards the origin along this vector.
3Step 3: Sketch Eigenvectors in the Phase Plane
Draw the vector \( \mathbf{v}_1 = \begin{bmatrix} 3 \ 1 \end{bmatrix} \) in the phase plane. This vector points in the direction where solutions will grow, forming trajectories that move outward. Draw the vector \( \mathbf{v}_2 = \begin{bmatrix} 1 \ 1 \end{bmatrix} \) where solutions will decay, forming trajectories that move inward toward the origin.
4Step 4: Plot Trajectories in the Phase Plane
Use the direction of eigenvectors to draw several solution curves. Start some trajectories near \( \mathbf{v}_1 \), showing they diverge exponentially. Start some trajectories near \( \mathbf{v}_2 \), showing convergence to the origin. Paths will tend to align with \( \mathbf{v}_2 \) as they approach the origin and with \( \mathbf{v}_1 \) as they move away.
5Step 5: Analyze the Stability of the Origin
With one positive and one negative eigenvalue, the origin is a saddle point. Solutions approach the origin along \( \mathbf{v}_2 \) and depart along \( \mathbf{v}_1 \), confirming the system's unstable nature.
Key Concepts
EigenvaluesEigenvectorsPhase Plane AnalysisStability Analysis
Eigenvalues
Eigenvalues play a crucial role in understanding the system of differential equations. They are values that indicate how the system will behave over time, particularly whether the system is stable, unstable, or oscillatory. In our case, the matrix \( A \) has two eigenvalues: \( \lambda_1 = 2 \) and \( \lambda_2 = -2 \).
Eigenvalues can be thought of as stretching or shrinking factors along certain directions.
Eigenvalues can be thought of as stretching or shrinking factors along certain directions.
- A positive eigenvalue, such as \( \lambda_1 = 2 \), means the system experiences exponential growth in the direction of its associated eigenvector.
- A negative eigenvalue, like \( \lambda_2 = -2 \), implies exponential decay.
Eigenvectors
Eigenvectors are fundamental for understanding the direction of these exponential behaviors dictated by eigenvalues. They determine the line along which solutions either grow or decay.
For the given problem:
For the given problem:
- The eigenvector associated with \( \lambda_1 = 2 \) is \( \mathbf{v}_1 = \begin{bmatrix} 3 \ 1 \end{bmatrix} \). In the phase plane, this means solutions start moving away from the origin along this vector.
- On the other hand, the eigenvector for \( \lambda_2 = -2 \) is \( \mathbf{v}_2 = \begin{bmatrix} 1 \ 1 \end{bmatrix} \), causing solutions to decay or move towards the origin.
Phase Plane Analysis
Phase plane analysis offers a visual depiction of the trajectories of differential equations, helping us understand the system's behavior at a glance. It's like a map of possible paths that solutions can take over time.
In our analysis:
In our analysis:
- The eigenvector \( \mathbf{v}_1 \) represents a path from which solutions rapidly escape the origin, leading to outward trajectories.
- Conversely, \( \mathbf{v}_2 \) directs solutions into the origin, forming inward trajectories.
Stability Analysis
Stability analysis lets us evaluate the equilibrium points of the system and determine if they are stable or unstable. It provides insight into how systems behave as time progresses. In our context, the origin is the equilibrium point.
With eigenvalues \( \lambda_1 = 2 \) and \( \lambda_2 = -2 \), we can easily assess the stability:
With eigenvalues \( \lambda_1 = 2 \) and \( \lambda_2 = -2 \), we can easily assess the stability:
- The presence of a positive eigenvalue indicates divergence from the origin, implying instability in certain directions.
- The negative eigenvalue signals convergence towards the origin in other directions.
Other exercises in this chapter
Problem 12
Write each system of linear differential equations in matrix notation. \(d x / d t=2 x-y \sin t, \quad d y / d t=y-x\)
View solution Problem 13
A Jacobian matrix and two equlibria are given. Determine if each is locally stable, unstable, or if the analysis is inconclusive. $$\begin{array}{l}{J=\left[ \b
View solution Problem 13
Write each system of linear differential equations in matrix notation. \(d x / d t=x+4 y-3 t, \quad d y / d t=y-x\)
View solution Problem 14
A Jacobian matrix and two equlibria are given. Determine if each is locally stable, unstable, or if the analysis is inconclusive. $$\begin{array}{l}{J=\left[ \b
View solution