Problem 13
Question
Simplify each expression. $$\sqrt{\frac{81}{5}}$$
Step-by-Step Solution
Verified Answer
The simplified expression is \( \frac{9\sqrt{5}}{5} \).
1Step 1: Simplify the Radical Expression
To simplify the expression \( \sqrt{\frac{81}{5}} \), first evaluate the square root of the numerator separately. The numerator is 81, which can be written as \( 9^2 \). Therefore, \( \sqrt{81} = 9 \).
2Step 2: Apply the Square Root to the Denominator
The square root of the denominator is \( \sqrt{5} \). Since 5 is not a perfect square, \( \sqrt{5} \) remains as it is.
3Step 3: Combine and Simplify the Expression
Now, combine the results from the numerator and the denominator. The expression \( \sqrt{\frac{81}{5}} = \frac{\sqrt{81}}{\sqrt{5}} = \frac{9}{\sqrt{5}} \).
4Step 4: Rationalize the Denominator
To complete the simplification, rationalize the denominator by multiplying both the numerator and the denominator by \( \sqrt{5} \): \[ \frac{9}{\sqrt{5}} \times \frac{\sqrt{5}}{\sqrt{5}} = \frac{9\sqrt{5}}{5} \]
5Step 5: Conclusion: Simplified Expression
The simplified expression for \( \sqrt{\frac{81}{5}} \) is \( \frac{9\sqrt{5}}{5} \).
Key Concepts
Square RootsRationalizing the DenominatorAlgebraic ExpressionsPerfect Squares
Square Roots
Square roots are a fundamental concept in mathematics, representing a value that, when multiplied by itself, gives the original number. For instance, the square root of 81 is 9 because \( 9 \times 9 = 81 \). The symbol used to denote a square root is \( \sqrt{} \).
In our example, we look at \( \sqrt{\frac{81}{5}} \). The first step is to calculate the square root of the numerator, 81. Since 81 is a perfect square, this calculation is simple. Understanding square roots helps in breaking down complex radicals into more manageable forms, especially when dealing with fractions or algebraic expressions.
Always remember that the square root operation can only yield non-negative results for real numbers, which is why we don't consider negative roots unless specified.
In our example, we look at \( \sqrt{\frac{81}{5}} \). The first step is to calculate the square root of the numerator, 81. Since 81 is a perfect square, this calculation is simple. Understanding square roots helps in breaking down complex radicals into more manageable forms, especially when dealing with fractions or algebraic expressions.
Always remember that the square root operation can only yield non-negative results for real numbers, which is why we don't consider negative roots unless specified.
Rationalizing the Denominator
Rationalizing the denominator involves removing any square roots from the denominator of a fraction. Typically, mathematicians prefer fractions with rational numbers (whole numbers or those that can be expressed as a fraction of two integers) in the denominator.
In the expression \( \frac{9}{\sqrt{5}} \), the denominator \( \sqrt{5} \) is not rational. To eliminate the square root, we multiply both the numerator and the denominator by \( \sqrt{5} \).
In the expression \( \frac{9}{\sqrt{5}} \), the denominator \( \sqrt{5} \) is not rational. To eliminate the square root, we multiply both the numerator and the denominator by \( \sqrt{5} \).
- The numerator becomes \( 9\sqrt{5} \).
- The denominator becomes \( \sqrt{5} \times \sqrt{5} = 5 \).
Algebraic Expressions
Algebraic expressions consist of numbers, variables, and operations. In simplifying radical expressions like \( \sqrt{\frac{81}{5}} \), understanding algebraic manipulation is key.
We initially handle the expression by considering both the numerator and the denominator separately, treating \( 81 \) and \( 5 \) as individual algebraic parts. We find the square root of 81 separately to simplify the process. By rationalizing the denominator, we further simplify the algebraic expression into a final manageable form, \( \frac{9\sqrt{5}}{5} \).
Skills in simplifying and manipulating such expressions are vital, especially when handling more complex formulas in algebra.
We initially handle the expression by considering both the numerator and the denominator separately, treating \( 81 \) and \( 5 \) as individual algebraic parts. We find the square root of 81 separately to simplify the process. By rationalizing the denominator, we further simplify the algebraic expression into a final manageable form, \( \frac{9\sqrt{5}}{5} \).
Skills in simplifying and manipulating such expressions are vital, especially when handling more complex formulas in algebra.
Perfect Squares
Perfect squares are integers that are the square of other integers. For example, 1, 4, 9, 16, 25, 36, and so on are perfect squares. These numbers are important because their square roots are whole numbers, simplifying many mathematical processes.
In the context of \( \sqrt{\frac{81}{5}} \), recognizing that 81 is a perfect square allows us to easily compute its square root, which is 9. This step reduces the complexity of the radical expression significantly.
Being able to identify perfect squares quickly is a useful skill that simplifies many mathematical problems, leading to faster and more efficient solutions.
In the context of \( \sqrt{\frac{81}{5}} \), recognizing that 81 is a perfect square allows us to easily compute its square root, which is 9. This step reduces the complexity of the radical expression significantly.
Being able to identify perfect squares quickly is a useful skill that simplifies many mathematical problems, leading to faster and more efficient solutions.
Other exercises in this chapter
Problem 13
For the following exercises, find the sum or difference. $$ \left(6 w^{2}+24 w+24\right)-(3 w-6 w+3) $$
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For the following exercises, simplify each expression. $$ \sqrt{\frac{81}{5}} $$
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For the following exercises, simplify the given expression. Write answers with positive exponents. $$ \left(8^{0}\right)^{2} $$
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Simplify the given expression. $$ 3-12 \cdot 2+19 $$
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