Problem 13
Question
Set up an equation and solve each of the following problems. (Objectives 1-3) How many milliliters of pure acid must be added to 100 milliliters of a \(10 \%\) acid solution to obtain a \(20 \%\) solution?
Step-by-Step Solution
Verified Answer
12.5 ml of pure acid must be added.
1Step 1: Understanding the Problem
We have 100 ml of a 10% acid solution and we are adding pure acid (100% acid) to this solution. We want the result to be a 20% acid solution. Our goal is to find the amount of pure acid that needs to be added.
2Step 2: Define Variables
Let the amount of pure acid to be added be represented by \( x \) milliliters. This means that the total volume of the solution after adding the acid will be \( 100 + x \) milliliters.
3Step 3: Set Up the Equation
Initially, we have 10% acid in a 100 ml solution, which means there are \( 0.1 \times 100 = 10 \) ml of acid. After adding \( x \) ml of pure acid, we will have \( 10 + x \) ml of acid. We want this to equal 20% of the total volume, \( 100 + x \). Thus, the equation is:\[ 10 + x = 0.2(100 + x) \]
4Step 4: Solve the Equation
Expand and simplify the equation:\[ 10 + x = 20 + 0.2x \]Subtract \(0.2x\) from both sides:\[ 10 + 0.8x = 20 \]Subtract 10 from both sides:\[ 0.8x = 10 \]Divide both sides by 0.8:\[ x = \frac{10}{0.8} = 12.5 \]
5Step 5: Verify the Solution
After adding 12.5 ml of pure acid, the total amount of acid is \( 10 + 12.5 = 22.5 \) ml. The total volume of the solution is \( 100 + 12.5 = 112.5 \) ml. The percentage of acid in the solution is \( \frac{22.5}{112.5} \times 100\% = 20\% \), confirming our solution is correct.
Key Concepts
Percent ConcentrationEquation SolvingMixture Problems
Percent Concentration
Percent concentration is a way to express the proportion of a substance in a mixture or solution. It is usually expressed in terms of percent by volume or mass, representing how much of a component is present relative to the total volume or mass of the mixture.
In the given problem, we start with a 10% acid solution. This indicates that 10% of the solution's volume is pure acid, while the remaining 90% is some other substance (often water).
This concept is pivotal when adjusting mixtures to reach a desired concentration. In practice, this can involve:
In the given problem, we start with a 10% acid solution. This indicates that 10% of the solution's volume is pure acid, while the remaining 90% is some other substance (often water).
This concept is pivotal when adjusting mixtures to reach a desired concentration. In practice, this can involve:
- Calculating the necessary amount of substance to adjust the concentration.
- Understanding how concentration changes with the addition or removal of components.
- Employing the concentration formula: \( \text{Concentration} = \frac{\text{Amount of Substance}}{\text{Total Volume}} \times 100\% \).
Equation Solving
Equation solving involves finding the value of unknown variables that satisfy given equations. It requires setting up equations based on the relationship described in a problem statement and then working systematically to solve them.
In this exercise, we define the unknown, \( x \), as the milliliters of pure acid to add. We construct an equation that represents the condition after mixing, \( 10 + x = 0.2(100 + x) \).
Here’s how to solve it step-by-step:
In this exercise, we define the unknown, \( x \), as the milliliters of pure acid to add. We construct an equation that represents the condition after mixing, \( 10 + x = 0.2(100 + x) \).
Here’s how to solve it step-by-step:
- First, identify known quantities and arrange them into an equation.
- Use algebra rules to simplify expressions (like distributing and combining like terms).
- Rearrange the equation to isolate the variable on one side.
- Solve the resulting expression for the unknown value.
Mixture Problems
Mixture problems require combining different substances to achieve a specific goal, like reaching a desired concentration. They often use systems of equations because mixtures bring together several variables to be solved simultaneously.
In this situation, we mixed pure acid with a pre-existing solution to increase the concentration. The key steps in handling mixture problems include:
In this situation, we mixed pure acid with a pre-existing solution to increase the concentration. The key steps in handling mixture problems include:
- Identifying the components of the mixture and their respective concentrations.
- Determining the desired outcome (such as final concentration or volume).
- Setting up equations which model these relationships and constraints.
- Solving these equations, often manipulating variables to achieve the goal.
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