Problem 13
Question
Prove that if \(\mathrm{A}\) is a strong deformation retract of \(\mathrm{X}\) then the inclusion map i: \(\mathrm{A} \rightarrow \mathrm{X}\) induces an isomorphism $$ \mathrm{i}_{*}: \pi(\mathrm{A}, \mathrm{a}) \rightarrow \pi(\mathrm{X}, \mathrm{a}) $$ for any point \(\mathrm{a} \in \mathrm{A}\).
Step-by-Step Solution
Verified Answer
The inclusion map induces an isomorphism because the loop's properties in both spaces are preserved.
1Step 1: Understanding the Concept
A strong deformation retract of a space \( \mathrm{X} \) onto a subspace \( \mathrm{A} \) means there exists a homotopy \( F: \mathrm{X} \times [0, 1] \to \mathrm{X} \) such that \( F(x, 0) = x \), \( F(x, 1) \in \mathrm{A} \) for all \( x \in \mathrm{X} \), \( F(a, t) = a \) for all \( a \in \mathrm{A} \) and \( t \in [0, 1] \). This essentially suggests that \( \mathrm{A} \) and \( \mathrm{X} \) have the same global topological properties up to homotopy.
2Step 2: Setup the Map i
The inclusion map \( i: \mathrm{A} \rightarrow \mathrm{X} \) is defined simply as including each element of \( \mathrm{A} \) as part of \( \mathrm{X} \). This will maintain the position, features, and properties of \( \mathrm{A} \) as a subspace in \( \mathrm{X} \).
3Step 3: Showing the Map i* Induces an Isomorphism
We need to show that the map \( i_*: \pi_1(\mathrm{A}, \mathrm{a}) \rightarrow \pi_1(\mathrm{X}, \mathrm{a}) \) is an isomorphism. A homotopy \( H \) shows \( i_* \) is both injective and surjective. Injectivity follows because any loop in \( \mathrm{A} \) that is homotopically trivial in \( \mathrm{X} \) will remain trivial when mapped back to \( \mathrm{A} \) via the retraction. Surjectivity follows because any loop in \( \mathrm{X} \) based at \( \mathrm{a} \) can be deformed to lie entirely within \( \mathrm{A} \), thanks to the properties of the deformation retract.
4Step 4: Verify Homotopy Equivalence
The result holds since the homotopy equivalence between \( \mathrm{A} \) and \( \mathrm{X} \) implies there exists a retraction map \( r: \mathrm{X} \rightarrow \mathrm{A} \) such that \( r \circ i \) is the identity map on \( \mathrm{A} \). Therefore, for any loop in \( \mathrm{X} \), \( r \) maps it back into loops in \( \mathrm{A} \), showing that \( i_* \) is bijective, hence an isomorphism.
Key Concepts
Strong Deformation RetractFundamental GroupHomotopyIsomorphism
Strong Deformation Retract
In algebraic topology, a strong deformation retract provides insight into how a subspace can mirror the structure of the larger space it is embedded in. Specifically, when a space \( \mathrm{X} \) can be transformed into a subspace \( \mathrm{A} \) through a continuous process, \( \mathrm{A} \) acts as a strong deformation retract of \( \mathrm{X} \). This is formalized using a homotopy \( F: \mathrm{X} \times [0, 1] \to \mathrm{X} \), which satisfies:
- \( F(x, 0) = x \) for all \( x \in \mathrm{X} \)
- \( F(x, 1) \in \mathrm{A} \) for all \( x \in \mathrm{X} \)
- \( F(a, t) = a \) for all \( a \in \mathrm{A}, \) and \( t \in [0, 1] \)
Fundamental Group
The fundamental group is a powerful tool in algebraic topology used to study topological spaces. Denoted as \( \pi_1(X, a) \), it captures the essence of a space's shape and properties based on loops emanating from a point \( a \). This group consists of equivalence classes of loops, where two loops are considered equivalent if one can be continuously transformed into the other without breaking or tearing the space.
- The power of this group comes from its ability to distinguish between different topological spaces.
- If two spaces have different fundamental groups, they are not topologically equivalent.
- The operation to combine two loops, called the loop product, forms the group structure.
Homotopy
Homotopy is a central concept in algebraic topology that explores the idea of continuously transforming one function or shape into another. When discussing topological spaces, a homotopy establishes a continuous deformation between two maps \( f, g: X \to Y \) over a parameter \( t \) in the interval \([0, 1]\). This continuous transformation is represented as \( H(x, t) \) such that:
- \( H(x, 0) = f(x) \) and \( H(x, 1) = g(x) \)
- For each fixed \( t \), \( H(x, t) \) itself is a function from \( X \) to \( Y \)
Isomorphism
In algebraic topology, an isomorphism implies a strong form of equality between mathematical structures. When we say that the inclusion map \( i_{*}: \pi_1(A, a) \to \pi_1(X, a) \) induces an isomorphism, it indicates that the fundamental groups of \( A \) and \( X \) are structurally the same. This means each element in \( \pi_1(A, a) \) corresponds uniquely to an element in \( \pi_1(X, a) \) and vice-versa.
- An isomorphism is bijective, covering both injectiveness (one-to-one) and surjectiveness (onto).
- It preserves the group operation, meaning if two loops are combined in \( A \), their image in \( X \) under the inclusion map behaves identically.
- In essence, it shows that two groups are indistinguishably equivalent in structure and function, thus serving as an algebraic manifestation of topological similarity.
Other exercises in this chapter
Problem 2
Show that \(\pi(X, x)=0\) if \(X\) is a finite topological space with the discrete topology.
View solution Problem 22
For \(S^{1} \subseteq C\) define \(\mu: \mathrm{S}^{1} \times \mathrm{S}^{1} \rightarrow \mathrm{S}^{1}\) by \(\mu\left(\mathrm{z}_{1}, \mathrm{~L}_{2}\right)=\
View solution