Problem 13
Question
Multiply or divide as indicated. $$ \sqrt{16} \cdot \sqrt{-1} $$
Step-by-Step Solution
Verified Answer
The result is \(4i\).
1Step 1: Simplify the Square Root of 16
The square root of 16 can be simplified, as it is a perfect square. Therefore, \( \sqrt{16} = 4 \).
2Step 2: Identify the Square Root of Negative One
The square root of \(-1\) is defined as the imaginary unit \(i\). That is, \(\sqrt{-1} = i\).
3Step 3: Multiply Simplified Radicals
After simplifying, we multiply the results from Steps 1 and 2: \( 4 \times i = 4i \).
Key Concepts
Square RootsImaginary UnitMultiplication of Radicals
Square Roots
Square roots are numbers that, when multiplied by themselves, produce a given number. For example, the square root of 16 is 4 because 4 times itself equals 16. Not every number has a simple square root like 16. When dealing with figures under a square root symbol, we are usually looking to find this value.
- Perfect Squares: Numbers like 1, 4, 9, 16, 25 are perfect squares since they are the result of squaring whole numbers.
- Calculating: To find the square root is like asking "What value multiplied by itself gives this number?"
Imaginary Unit
The imaginary unit, denoted as \(i\), is crucial in mathematics, especially when dealing with square roots of negative numbers. The imaginary unit \(i\) is defined by the equation \(i^2 = -1\). This definition allows us to expand our number system to include "imaginary numbers."
- Imaginary Numbers: Numbers that involve \(i\), such as \(i\), \(2i\), \(3 + 4i\).
- Purpose: Imaginary numbers are essential for solving equations like \(x^2 + 1 = 0\), where a solution doesn't exist within the real numbers alone.
Multiplication of Radicals
Multiplication of radicals is a process where we multiply terms that are within square root symbols. When multiplying radicals like \(\sqrt{a} \cdot \sqrt{b}\), the product rule for roots is typically applied.
- Product Rule: \(\sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b}\).
- Practical Example: In the original exercise, we had \(\sqrt{16} \cdot \sqrt{-1}\), where we first simplified \(\sqrt{16}\) and recognized \(\sqrt{-1}\) as \(i\).
Other exercises in this chapter
Problem 13
Add or subtract as indicated. Assume that all variables represent positive real numbers. $$ \sqrt[3]{\frac{11}{8}}-\frac{\sqrt[3]{11}}{6} $$
View solution Problem 13
Use the quotient rule to simplify. Assume that all variables represent positive real numbers. $$ \sqrt{\frac{6}{49}} $$
View solution Problem 14
Solve. $$ \sqrt[3]{2 x-6}-4=0 $$
View solution Problem 14
Rationalize each denominator. Assume that all variables represent positive real numbers. \(\frac{5}{\sqrt[3]{9}}\)
View solution