Problem 13
Question
Let \(z_{k} \neq 1\) be an \(n\) th root of unity. Prove that \(1+z_{k}+z_{k}^{2}+\cdots+z_{k}^{n-1}=0\).
Step-by-Step Solution
Verified Answer
The sum of the nth roots of unity (excluding 1) is zero: \(1+z_k+z_k^2+\cdots+z_k^{n-1}=0\).
1Step 1: Understand the Definition of nth Root of Unity
An \(n\)th root of unity is a complex number \(z_k\) such that \(z_k^n = 1\). The different \(n\)th roots of unity are \(1, \omega, \omega^2, \ldots, \omega^{n-1}\) where \(\omega = e^{2\pi i / n}\). Each root corresponds to different powers of \(\omega\).
2Step 2: Form the Sum of Powers of z_k
Consider the series \(1 + z_k + z_k^2 + \cdots + z_k^{n-1}\). This is a geometric series with \(n\) terms, first term \(a = 1\), and common ratio \(r = z_k\).
3Step 3: Apply the Geometric Series Sum Formula
The sum of a geometric series is given by the formula: \[ S_n = \frac{a(1-r^n)}{1-r} \]Here, substitute \(a = 1\) and \(r = z_k\), giving:\[ S_n = \frac{1(1 - z_k^n)}{1 - z_k} \].
4Step 4: Simplify Using the Property of z_k
Since \(z_k\) is an \(n\)th root of unity, by definition, \(z_k^n = 1\). Substitute this into the sum formula:\[ S_n = \frac{1 - 1}{1 - z_k} = \frac{0}{1 - z_k} = 0 \].
5Step 5: Conclusion on the Sum
As calculated, \(1 + z_k + z_k^2 + \cdots + z_k^{n-1} = 0\) for any \(n\)th root of unity where \(z_k eq 1\). This result depends on the property that the powers of roots of unity sum to zero except for the entire cycle including \(z_k=1\).
Key Concepts
Geometric SeriesComplex NumberSum of Roots of Unity
Geometric Series
A geometric series is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed, non-zero number called the common ratio. This series takes the form:
- First term: \(a\)
- Common ratio: \(r\)
Complex Number
Complex numbers expand our number system to include solutions to equations like \(x^2 + 1 = 0\). They are written in the form \(a + bi\), where \(a\) is the real part and \(b\) is the imaginary part.
- Real part: \(a\)
- Imaginary part: \(b\)
- Imaginary unit \(i\): Represents the square root of -1, fulfilling \(i^2 = -1\)
Sum of Roots of Unity
The sum of the nth roots of unity (excluding the root which equals 1) is zero. This feature arises from their symmetric arrangement on the complex plane.Consider the nth roots of unity: These can be represented as powers of \(\omega\), where \(\omega = e^{2\pi i / n}\), forming the sequence:
- 1
- \(\omega\)
- \(\omega^2\)
- \(\cdots\)
- \(\omega^{n-1}\)
Other exercises in this chapter
Problem 13
Show that the equation of the line through the points \(z_{1}\) and \(z_{2}\) can be expressed in the form \(z=z_{1}+t\left(z_{2}-z_{1}\right)\), where \(t\) is
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Show that if \(z \neq 0\), then (a) \(\operatorname{Arg}(z \bar{z})=0\). (b) \(\operatorname{Arg}(z+\bar{z})=0\) when \(\operatorname{Re}(z)>0\).
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Let \(S\) be the open set consisting of all points \(z\) such that \(|z+2|
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Show that the nonzero vectors \(z_{1}\) and \(z_{2}\) are parallel iff \(\operatorname{Im}\left(z_{1} \overline{z_{2}}\right)=0\).
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