Problem 13
Question
Let \(\widetilde{\mathbb{C}}\) be another field of complex numbers. Determine all mappings \(\varphi: \mathbb{C} \rightarrow \widetilde{\mathbb{C}}\) with the following properties: (a) \(\varphi(z+w)=\varphi(z)+\varphi(w) \quad\) for all \(z, w \in \mathbb{C}\) (b) \(\varphi(z w)=\varphi(z) \varphi(w) \quad\) for all \(z, w \in \mathbb{C}\) \(\begin{array}{cll}(c) & \varphi(x)=x & \text { for all } x \in \mathbb{R} \text {. }\end{array}\) Remark. It turns out that such mappings exist, and they are automatically bijective; thus they give isomorphisms \(\mathbb{C} \rightarrow \widetilde{\mathbb{C}}\) that leave \(\mathbb{R}\) elementwise fixed. The field of complex numbers is therefore essentially uniquely determined. In the special case \(\mathbb{C}=\widetilde{\mathbb{C}}\) we get automorphisms of \(\mathbb{C}\) with the fixed field \(\mathbb{R}\). Remark. What automorphisms (i.e. isomorphisms onto itself) admits the field of real numbers \(\mathbb{R}\) ? Hint. Such an automorphism of \(\mathbb{R}\) must preserve the ordering, of \(\mathbb{R} !\)
Step-by-Step Solution
VerifiedKey Concepts
Field Automorphisms
- Field automorphisms act like mirrors that reflect the field's inherent properties.
- These mappings are always bijective, meaning they pair elements one-to-one between fields.
Additive and Multiplicative Properties
- These properties ensure that each operation within the field maintains its natural mathematical flow.
- It’s like translating a novel while keeping the storyline and tone intact.
Real Number Field
- Real numbers form the backbone of more complex structures, providing a stable reference.
- Ensuring the identity property helps stabilize and reflect the inherent order of \( \mathbb{R} \).