Problem 13
Question
Let \(f(x)=2 x^{2}+x-3\) and \(g(x)=x-1 .\) Perform each function operation and then find the domain. $$ f(x)+g(x) $$
Step-by-Step Solution
VerifiedKey Concepts
Function Operations
- To add functions, you simply add like terms. For the functions given:
- \(f(x) = 2x^2 + x - 3\)
- \(g(x) = x - 1\)
- \((f + g)(x) = f(x) + g(x) = (2x^2 + x - 3) + (x - 1)\)
- \((f + g)(x) = 2x^2 + 2x - 4\)
The sum is found by combining these terms:
This results in a new function:
This process maintains the structure of a polynomial function. Adding functions is straightforward and follows the same rules as adding polynomial expressions.
Domain of Functions
For most polynomial functions, there are no restrictions on the values of \(x\) that you can input, meaning their domain is all real numbers. This is because polynomial functions do not have any operations that would cause undefined values, such as division by zero or taking the square root of a negative number.In this case, the result of our function operation is:
- \((f + g)(x) = 2x^2 + 2x - 4\)
Since this is a simple quadratic polynomial, its domain is all real numbers.Whenever dealing with polynomial functions, it's safe to assume their domain is unrestricted, unless specified otherwise.
Real Numbers
- Positive numbers (e.g., 1, 2.5)
- Negative numbers (e.g., -3, -0.75)
- Zero
- Rational numbers (fractions and decimals)
- Irrational numbers (e.g., \(\sqrt{2}\), \(\pi\))
In the context of polynomial functions like \((f + g)(x) = 2x^2 + 2x - 4\), all these real numbers can be used as input values. They form the function's domain.Using real numbers for polynomial functions means that there are no limits to the \(x\) values. This makes them very adaptable and applicable in numerous mathematical scenarios and everyday calculations.