Problem 13
Question
Let \(A\) be the given matrix. Find det \(A\) by using the method of co factors. $$ \left[\begin{array}{lll} 2 & 0 & 0 \\ 0 & 3 & 0 \\ 0 & 0 & 5 \end{array}\right] $$
Step-by-Step Solution
Verified Answer
The determinant of matrix \(A\) is 30.
1Step 1: Identify the Matrix and Recall Definition
We start with matrix \(A\) given as \(\begin{bmatrix} 2 & 0 & 0 \ 0 & 3 & 0 \ 0 & 0 & 5 \end{bmatrix}\). The determinant of a 3x3 diagonal matrix \( \begin{bmatrix} a & 0 & 0 \ 0 & b & 0 \ 0 & 0 & c \end{bmatrix} \) is directly equal to the product of its diagonal elements \( a \cdot b \cdot c \).
2Step 2: Apply the Definition of Determinant for Diagonal Matrices
Since the matrix \(A\) is a diagonal matrix, we can find the determinant by multiplying its diagonal elements. Thus, \( \text{det}(A) = 2 \times 3 \times 5 \).
3Step 3: Calculate Det(A)
Perform the multiplication of the diagonal elements: \( 2 \times 3 = 6 \) and then \( 6 \times 5 = 30 \). So, the determinant \( \text{det}(A) = 30 \).
4Step 4: Conclusion
The determinant of the matrix \(A\) is 30. There was no need to expand by cofactors since it's a diagonal matrix.
Key Concepts
Diagonal MatricesCofactor ExpansionDeterminant Calculation
Diagonal Matrices
A diagonal matrix is a special kind of square matrix. It simplifies many calculations in linear algebra because all non-diagonal elements are zero. This means it's presented in a format where everything outside its main diagonal is zero, like the matrix from the original exercise:
This property makes calculating determinants of diagonal matrices very efficient. Instead of going through complex cofactor expansions, you simply multiply the diagonal elements.
- The elements along the diagonal are called diagonal elements, and in a 3x3 matrix, these are placed at positions (1,1), (2,2), and (3,3).
- Diagonal matrices are simple to work with, as their determinant is just the product of these diagonal elements.
This property makes calculating determinants of diagonal matrices very efficient. Instead of going through complex cofactor expansions, you simply multiply the diagonal elements.
Cofactor Expansion
The concept of cofactor expansion is key for determining the determinant of a matrix, especially when you're not dealing with diagonal matrices. It involves breaking down larger matrices into smaller ones, focusing on minors and signatures. Here's a rundown of what happens:
- Choose a row or column. This affects the computation method but not the end result.
- Calculate the minor for each element in this row or column by removing the respective row and column, simplifying your work to a smaller matrix.
- Multiply each minor by the element in the original matrix and the corresponding sign from the sign pattern (+, -, +).
Determinant Calculation
Determinants are an important aspect of linear algebra, offering insight into matrix properties such as invertibility or eigenvalues. Usually, the determinant is calculated using cofactor expansion or, in special cases like diagonal matrices, by straightforward multiplication of elements from the main diagonal.
When calculating determinants:
- Check if the matrix is special, like diagonal or triangular. This often allows for simple computation.
- For regular matrices, apply cofactor expansion if necessary.
- Carry out multiplications and any necessary calculations sequentially to prevent errors.
Other exercises in this chapter
Problem 12
If possible, solve the system. $$ \begin{aligned} x-y+z &=2 \\ 3 x-2 y+z &=-1 \\ x+y &=-3 \end{aligned} $$
View solution Problem 13
For the given matrices \(A\) and \(B\) find each of the following. (a) \(\boldsymbol{A}+\boldsymbol{B} \quad\) (b) \(\boldsymbol{B}+\boldsymbol{A} \quad(\boldsy
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Predict the results of \(I_{n} A\) and \(A I_{n}\). Then verify your prediction. $$ I_{3}=\left[\begin{array}{lll} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{arra
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The augmented matrix is in row-echelon form and represents a linear system. Solve the system by using backwand substitution, if possible. Write the solution as
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