Problem 13
Question
\(\left(9 x^{-3}\right)\left(4 x^{5}\right)\)
Step-by-Step Solution
Verified Answer
36x^{2}
1Step 1 - Identify the expression components
Look at the expression \( \left(9 x^{-3}\right)\left(4 x^{5}\right) \ \). There are two main parts: a coefficient and a variable with an exponent in each term.
2Step 2 - Multiply the coefficients
Multiply the coefficients of each term: \( 9 \text{ and } \ 4 \). The product is \ 9 \times 4 = 36.\
3Step 3 - Add the exponents
Apply the property of exponents that states \ x^a \cdot x^b = x^{a+b} \ \. Add the exponents of \( x \) in the expression \( x^{-3} \ and \ x^{5} \). The sum of the exponents is \ -3 + 5 = 2 \.
4Step 4 - Combine the results
Combine the product of the coefficients and the sum of the exponents to rewrite the expression. Thus, \( 36 x^{2} \ \).
Key Concepts
CoefficientsExponentsSimplifying ExpressionsProperties of Exponents
Coefficients
A coefficient is the numerical part of a term that includes a variable. For example, in the expression \(9x^{-3}\), 9 is the coefficient as it represents how many units of \(x^{-3}\) are included. Identifying coefficients is crucial when multiplying expressions since it is one of the first steps. Recall that when multiplying two terms, you first multiply the coefficients. In the exercise, the coefficients 9 and 4 were identified, and their product was calculated as follows:
\(9 \times 4 = 36\).
By separating numerical parts (coefficients) from the variables, you simplify the multiplication process.
\(9 \times 4 = 36\).
By separating numerical parts (coefficients) from the variables, you simplify the multiplication process.
Exponents
An exponent tells you how many times a base (like \(x\) in our exercise) is multiplied by itself. For instance, in \(x^{-3}\), -3 is the exponent and indicates reciprocal action. Negative exponents, like in our example \(x^{-3}\), can be tricky but follow consistent rules. When you have \(x^{-a}\), it translates to the reciprocal of \(x^a\). In our case, we consider exponents while multiplying because they follow specific properties that make the simplification process smoother.
Simplifying Expressions
Simplifying expressions means reducing them to their simplest form. In the exercise, this involves both coefficients and exponents in the following steps:
- Multiply coefficients: From \(9x^{-3}\) and \(4x^5\), we got \(9 \times 4 = 36\).
- Add exponents: Using the rule - \(x^a \times x^b = x^{a+b}\) - combining\(x^{-3}\) and \(x^5\) gives \(x^{-3+5} = x^2\).
Properties of Exponents
When dealing with exponents, certain rules make the calculations easy and consistent. For multiplication, the primary property is:
\[x^a \times x^b = x^{a+b}\].
This means you add the exponents of the same base. This property was applied in our exercise to combine \(x^{-3}\) and \(x^5\). Understanding this rule ensures you handle various exponents scenarios correctly. Subtracting the negative exponent from a positive one, as done here, yields the straightforward \(x^2\). Using the properties of exponents correctly simplifies complex expressions efficiently.
\[x^a \times x^b = x^{a+b}\].
This means you add the exponents of the same base. This property was applied in our exercise to combine \(x^{-3}\) and \(x^5\). Understanding this rule ensures you handle various exponents scenarios correctly. Subtracting the negative exponent from a positive one, as done here, yields the straightforward \(x^2\). Using the properties of exponents correctly simplifies complex expressions efficiently.
Other exercises in this chapter
Problem 13
\(\left(56 u^{5}-64 u^{3}+72 u^{2}\right) \div\left(8 u^{2}\right)\)
View solution Problem 13
The prefix tri means "three." State an English word besides trinomial that includes the prefix tri. Explain the meaning of the word.
View solution Problem 14
\(\left(72 v^{6}-81 v^{4}+54 v^{2}\right) \div\left(9 v^{2}\right)\)
View solution Problem 14
The prefix mono means "one." State an English word besides monomial that includes the prefix mono. Explain the meaning of the word.
View solution