Problem 13
Question
In Reaction \(15.7\), water is shown acting as a base. How is water behaving in the following reaction? $$ \mathrm{NH}_{2}^{-}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{NH}_{3}+\mathrm{OH}^{-} $$ Explain your answer.
Step-by-Step Solution
Verified Answer
In the reaction \(\mathrm{NH}_{2}^{-}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{NH}_{3}+\mathrm{OH}^{-}\), water is behaving as an acid because it donates a hydrogen ion (H+) to the \(\mathrm{NH}_{2}^{-}\) ion, resulting in the formation of \(\mathrm{NH}_{3}\) and \(\mathrm{OH}^{-}\).
1Step 1: Understand the role of acids and bases
Acids are substances that donate a hydrogen ion (H+), while bases are substances that accept a hydrogen ion. In a reaction, when a molecule accepts a hydrogen ion, it is functioning as a base; while if it donates a hydrogen ion, it is functioning as an acid.
2Step 2: Identify the reactants and products of the reaction
In the given reaction:
$$
\mathrm{NH}_{2}^{-}+\mathrm{H}_{2} \mathrm{O} \rightarrow
\mathrm{NH}_{3}+\mathrm{OH}^{-}
$$
The reactants are \(\mathrm{NH}_{2}^-\) and \(\mathrm{H}_{2} \mathrm{O}\), while the products are \(\mathrm{NH}_{3}\) and \(\mathrm{OH}^{-}\).
3Step 3: Study the water molecule in the reaction
In the reaction:
$$
\mathrm{NH}_{2}^{-}+\mathrm{H}_{2} \mathrm{O} \rightarrow
\mathrm{NH}_{3}+\mathrm{OH}^{-}
$$
Water is one of the reactants and participates by giving away one of its hydrogen ions (H+) to the \(\mathrm{NH}_{2}^-\) ion.
4Step 4: Determine how water is behaving in the reaction
When \(\mathrm{H}_{2}\mathrm{O}\) donates a hydrogen ion to \(\mathrm{NH}_{2}^{-}\) to form \(\mathrm{NH}_{3}\), it leaves behind an \(\mathrm{OH}^{-}\) ion. Since water is donating a hydrogen ion (H+) in the reaction, it is functioning as an acid.
5Step 5: Provide the explanation
In the given reaction, water is behaving as an acid because it donates a hydrogen ion (H+) to the \(\mathrm{NH}_{2}^{-}\) ion, resulting in the formation of \(\mathrm{NH}_{3}\) and \(\mathrm{OH}^{-}\).
Key Concepts
Bronsted-Lowry Acids and BasesChemical ReactionsProton Transfer
Bronsted-Lowry Acids and Bases
When discussing the Bronsted-Lowry theory, it's all about the transfer of protons, specifically hydrogen ions (H+). According to this theory, a substance that donates a proton is termed as an acid, while the one that accepts a proton is known as a base. It's essential to think of protons as lightweight particles that are often traded in chemical reactions.
Take hydronium ion \(\mathrm{H}_3\mathrm{O}^+\)as an example. It acts as a Bronsted-Lowry acid because it can donate a proton to another substance, leaving behind a water molecule. Similarly, ammonia \(\mathrm{NH}_3\) can accept a proton from water, making it a Bronsted-Lowry base, as it forms ammonium \(\mathrm{NH}_4^+\).
Take hydronium ion \(\mathrm{H}_3\mathrm{O}^+\)as an example. It acts as a Bronsted-Lowry acid because it can donate a proton to another substance, leaving behind a water molecule. Similarly, ammonia \(\mathrm{NH}_3\) can accept a proton from water, making it a Bronsted-Lowry base, as it forms ammonium \(\mathrm{NH}_4^+\).
- Acids: Proton donors
- Bases: Proton acceptors
Chemical Reactions
Chemical reactions involve the transformation of substances through the breaking and forming of bonds. In the context of the acid-base reaction detailed here, the focus is on how molecules interact to transfer hydrogen ions.
In the reaction \( \mathrm{NH}_2^{-} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{NH}_3 + \mathrm{OH}^{-} \), the key players are hydroxide \(\mathrm{OH}^{-}\)and water \(\mathrm{H}_2\mathrm{O}\). Water starts by donating a proton. This process decreases water's hydrogen count and converts it into hydroxide.
In the reaction \( \mathrm{NH}_2^{-} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{NH}_3 + \mathrm{OH}^{-} \), the key players are hydroxide \(\mathrm{OH}^{-}\)and water \(\mathrm{H}_2\mathrm{O}\). Water starts by donating a proton. This process decreases water's hydrogen count and converts it into hydroxide.
- Reactants interact in a specific pathway
- Sometimes substances can have dual roles, acting differently depending on conditions
Proton Transfer
Proton transfer is central in many reactions, particularly in acid-base chemistry. It's the movement of a proton from one molecule to another, reshaping their identities in the process.
In the given reaction \( \mathrm{NH}_2^{-} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{NH}_3 + \mathrm{OH}^{-} \), \(\mathrm{H}_2\mathrm{O}\)donates a proton to \(\mathrm{NH}_2^{-}\), converting it into \(\mathrm{NH}_3\). Water becomes a donor here, as it transfers a proton and consequently becomes hydroxide \(\mathrm{OH}^{-}\).
In the given reaction \( \mathrm{NH}_2^{-} + \mathrm{H}_2\mathrm{O} \rightarrow \mathrm{NH}_3 + \mathrm{OH}^{-} \), \(\mathrm{H}_2\mathrm{O}\)donates a proton to \(\mathrm{NH}_2^{-}\), converting it into \(\mathrm{NH}_3\). Water becomes a donor here, as it transfers a proton and consequently becomes hydroxide \(\mathrm{OH}^{-}\).
- Proton transfer shifts chemical balance
- Transforms reactants to products
- Essential in defining roles of acids and bases
Other exercises in this chapter
Problem 9
How many moles of \(\mathrm{Ba}(\mathrm{OH})_{2}\) would it take to neutralize \(0.1\) mole of hydrochloric acid?
View solution Problem 11
In the reaction $$ \mathrm{NH}_{3}+\mathrm{PH}_{3} \rightarrow \mathrm{NH}_{2}^{-}+\mathrm{PH}_{4}^{+} $$ which reactant is the Bronsted-Lowry acid and which is
View solution Problem 14
Aniline, \(\mathrm{C}_{6} \mathrm{H}_{7} \mathrm{~N}\), is a molecular compound that is a weak base. The molecule has a lone pair of electrons on the \(\mathrm{
View solution Problem 15
In the presence of water, the bicarbonate ion, \(\mathrm{HCO}_{3}^{-}\), can be either a BronstedLowry acid or a Bronsted-I.owry base. Write both equilibrium eq
View solution