Problem 13
Question
In Problems 11-14, write the number given in polar form in the form \(a+i b\). $$ z=6\left(\cos \frac{\pi}{8}+i \sin \frac{\pi}{8}\right) $$
Step-by-Step Solution
Verified Answer
The number in Cartesian form is approximately \(5.5434 + 2.2962i\).
1Step 1: Understanding the Polar Form
The given complex number is in polar form: \( z = 6(\cos \frac{\pi}{8} + i \sin \frac{\pi}{8}) \). This means the complex number is represented as \( r(\cos\theta + i\sin\theta) \), where \( r = 6 \) and \( \theta = \frac{\pi}{8} \). Our goal is to convert this to Cartesian form, \( a + ib \).
2Step 2: Using Trigonometric Values
Find the values of \( \cos \frac{\pi}{8} \) and \( \sin \frac{\pi}{8} \). These are standard trigonometric values. Using a calculator or trigonometric tables:\[\cos \frac{\pi}{8} = \frac{\sqrt{2+\sqrt{2}}}{2} \approx 0.9239\]\[\sin \frac{\pi}{8} = \frac{\sqrt{2-\sqrt{2}}}{2} \approx 0.3827\]
3Step 3: Calculating the Real Part
Obtain the real part by multiplying \( r \) by \( \cos \theta \):\[a = 6 \times \cos \frac{\pi}{8} = 6 \times 0.9239 = 5.5434\]
4Step 4: Calculating the Imaginary Part
Obtain the imaginary part by multiplying \( r \) by \( \sin \theta \):\[b = 6 \times \sin \frac{\pi}{8} = 6 \times 0.3827 = 2.2962\]
5Step 5: Combining Real and Imaginary Parts
Combine the real and imaginary parts to express the complex number in the form \( a + ib \):\[z = 5.5434 + 2.2962i\]
Key Concepts
Polar FormCartesian FormTrigonometric ValuesReal and Imaginary Parts
Polar Form
Understanding the polar form of complex numbers is crucial, especially when dealing with mathematical problems involving angles and magnitudes. The polar form expresses a complex number based on its distance from the origin, known as the *modulus*, and its angle from the positive x-axis, known as the *argument*.
Imagine representing a complex number on the complex plane; the polar form is like plotting it using polar coordinates. This form is typically written as \( r (\cos \theta + i \sin \theta) \), where:
Imagine representing a complex number on the complex plane; the polar form is like plotting it using polar coordinates. This form is typically written as \( r (\cos \theta + i \sin \theta) \), where:
- \( r \) is the modulus or magnitude, which is the distance from the origin to the point.
- \( \theta \) is the argument, representing the angle.
- The combination of these gives you a way to describe any complex number on the plane.
Cartesian Form
The Cartesian form of a complex number, also known as the rectangular form, is expressed as \( a + ib \), where \( a \) is the real part and \( b \) is the imaginary part. This form allows one to easily visualize or perform algebraic operations on complex numbers.
To convert a complex number from polar to Cartesian form, you multiply the modulus \( r \) by the cosine of the angle \( \theta \) to find the real part \( a \), and by the sine of \( \theta \) to find the imaginary part \( b \).
To convert a complex number from polar to Cartesian form, you multiply the modulus \( r \) by the cosine of the angle \( \theta \) to find the real part \( a \), and by the sine of \( \theta \) to find the imaginary part \( b \).
- The process: \( a = r \cos \theta \) and \( b = r \sin \theta \).
- Combine these to get \( a + ib \).
Trigonometric Values
Understanding and using trigonometric values is key to converting complex numbers between forms. Trigonometric values for angles plotted on the circle, especially standard angles, are useful for precise mathematical work.
In the given exercise, we need \( \cos \frac{\pi}{8} \) and \( \sin \frac{\pi}{8} \). Using trigonometric tables or a calculator, you obtain:
In the given exercise, we need \( \cos \frac{\pi}{8} \) and \( \sin \frac{\pi}{8} \). Using trigonometric tables or a calculator, you obtain:
- \( \cos \frac{\pi}{8} \approx 0.9239 \),
- \( \sin \frac{\pi}{8} \approx 0.3827 \).
Real and Imaginary Parts
Decomposing a complex number into its real and imaginary parts is necessary for various applications in mathematics and engineering. These parts allow us to handle complex quantities in a way that separates magnitude and direction.
The real part \( a \) is obtained from the product of the modulus \( r \) and the cosine of the angle \( \theta \), while the imaginary part \( b \) results from multiplying \( r \) with the sine of \( \theta \).
The real part \( a \) is obtained from the product of the modulus \( r \) and the cosine of the angle \( \theta \), while the imaginary part \( b \) results from multiplying \( r \) with the sine of \( \theta \).
- Real part: \( a = r \cos \theta \)
- Imaginary part: \( b = r \sin \theta \)
- \( a = 6 \times 0.9239 = 5.5434 \)
- \( b = 6 \times 0.3827 = 2.2962 \)
Other exercises in this chapter
Problem 13
In Problems 7-14, express the given function in the form \(f(z)=u+i v .\) $$ f(z)=z+1 / z $$
View solution Problem 13
In Problems 9-22, sketch the set of points in the complex plane satisfying the given inequality. Determine whether the set is a domain. $$ 2
View solution Problem 13
In Problems 1-26, write the given number in the form \(a+i b\). $$ \frac{2}{i} $$
View solution Problem 14
Sketch the set of points in the complex plane satisfying the given inequality. Determine whether the set is a domain. $$ -1 \leq \operatorname{Im}(z)
View solution