Problem 13
Question
In Exercises \(7 - 14 ,\) determine the limit by substitution. Support graphically. $$\lim _ { x \rightarrow - 2 } ( x - 6 ) ^ { 2 / 3 }$$
Step-by-Step Solution
Verified Answer
Therefore, the solution to \(\lim _ { x \rightarrow - 2 } (x - 6) ^ {2 / 3}\) is \(4\).
1Step 1: Substitute x in the function
According to the limit's substitution principle, first, we need to substitute \(x = -2\) into the function \((x - 6)^{2/3}\). So our function will change into \((-2 - 6)^{2/3}\).
2Step 2: Solving the Expression
After substituting \(x=-2\) into the function, let's solve the equation \((-2 - 6)^{2/3}\). First, calculate the result of \(-2 - 6\), which equals \(-8\). Now the equation becomes \((-8)^{2/3}\.
3Step 3: Calculating the Cube Root
Next, let's simplify the equation further. The cube root of -8 is -2. So, \((-8)^{2/3}\) equals to \((-2)^2\), which is \(4\). Therefore, the limit of the function \((x - 6)^{2/3}\) as \(x\) approaches \(-2\) is \(4\).
4Step 4: Graphical Representation
When graphing the function \((x - 6)^{2/3}\), we will observe that as \(x\) approaches \(-2\), the function approaches \(4\). This graphical representation confirms the limit found algebraically.
Key Concepts
Limit by SubstitutionAlgebraic ManipulationGraphical RepresentationCube Roots
Limit by Substitution
Understanding the concept of limit by substitution is a foundational skill in calculus. It involves directly substituting the value into the function when finding the limit. This technique works effectively for functions that are continuous at the given point. In our exercise, this means replacing
- \(x = -2\)
- into the expression \((x-6)^{2/3}\).
- \((-2-6)^{2/3}\).
Algebraic Manipulation
After substitution, algebraic manipulation helps simplify the expression to find the exact limit. In the exercise,
Algebraic manipulation involves calculating powers and roots in this case. By finding the cube root of \(-8\), which is \(-2\), and then squaring the result, we simplify
- we initially solve for \(-2 - 6\), which simplifies to \(-8\).
- \((-8)^{2/3}\).
Algebraic manipulation involves calculating powers and roots in this case. By finding the cube root of \(-8\), which is \(-2\), and then squaring the result, we simplify
- \((-8)^{2/3}\) to \((-2)^2 = 4\).
Graphical Representation
Graphical representation offers a visual perspective on limits. Plotting the function provides an understanding of how it behaves around certain points. For the function
The graph should show the function approaching the value of \(4\). Visual confirmation through graphs supports the algebraic calculations and enriches comprehension. This method highlights whether the limit is continuous or if any discontinuity exists. Graphs are beneficial in identifying trends, asymptotic behaviors, and verifying calculated limits.
- \((x-6)^{2/3}\),
- we analyze its curve as \(x\) approaches \(-2\).
The graph should show the function approaching the value of \(4\). Visual confirmation through graphs supports the algebraic calculations and enriches comprehension. This method highlights whether the limit is continuous or if any discontinuity exists. Graphs are beneficial in identifying trends, asymptotic behaviors, and verifying calculated limits.
Cube Roots
Cube roots play a crucial role in simplifying expressions such as \((-8)^{2/3}\). A cube root is a value that, when multiplied by itself twice, yields the original number. In our case:
Understanding cube roots is vital, as they frequently appear in calculus when dealing with radical expressions. Mastering this concept allows for accurate simplification and solution of complex limit problems.
- The cube root of \(-8\) is \(-2\).
- This simplifies the expression to \((-2)^2 = 4\).
Understanding cube roots is vital, as they frequently appear in calculus when dealing with radical expressions. Mastering this concept allows for accurate simplification and solution of complex limit problems.
Other exercises in this chapter
Problem 12
In Exercises \(11-18,\) use the function \(f\) defined and graphed below to answer the questions. $$f(x)=\left\\{\begin{array}{ll}{x^{2}-1,} & {-1 \leq x
View solution Problem 13
In Exercises 13 and \(14,\) find the slope of the curve at the indicated point. $$f(x)=|x| \quad\( at \)\quad\( (a) \)x=2 \quad\( (b) \)x=-3$$
View solution Problem 13
In Exercises \(11-18,\) use the function \(f\) defined and graphed below to answer the questions. $$f(x)=\left\\{\begin{array}{ll}{x^{2}-1,} & {-1 \leq x
View solution Problem 13
In Exercises 13-20, use graphs and tables to find the limits. $$\lim _{x \rightarrow 2^{+}} \frac{1}{x-2}$$
View solution