Problem 13
Question
In Exercises \(5-18,\) solve each system by the substitution method. $$ \left\\{\begin{array}{l} 2 x+5 y=-4 \\ 3 x-y=11 \end{array}\right. $$
Step-by-Step Solution
Verified Answer
The solution to the system of equations is x = 3, y = -2
1Step 1: Isolate one variable in one equation
Isolate the variable y in equation 2:\n3x - y = 11 implies y = 3x - 11
2Step 2: Substitute the value of y into the other equation
Substitute y = 3x-11 from equation 2 into equation 1: \n2x + 5(3x - 11) = -4, which simplifies to 17x = 51
3Step 3: Solve for variable x
Solve the equation from the second step to find x: \n17x = 51 gives x = 3
4Step 4: Substitute value of x into y equation
Substitute x = 3 into the previously isolated y equation: \ny = 3(3) - 11 = -2
5Step 5: Check the solution
Substitute x = 3 and y = -2 in the original equations:\n2(3) + 5(-2) = -4 and 3(3) - (-2) = 11. Both are true, therefore the solution is correct
Key Concepts
Understanding Systems of EquationsLinear Equations in AlgebraEffective Algebra Problem Solving Using Substitution Method
Understanding Systems of Equations
A system of equations is a set of two or more equations that have common variables. These equations work together, and we're tasked with finding values for these variables that satisfy all the equations simultaneously. In our example, the equations provided are:
- \(2x + 5y = -4\)
- \(3x - y = 11\)
Linear Equations in Algebra
Linear equations are a type of equation where the variables appear in a linear form, meaning they have no exponents or powers other than one. They are represented graphically as straight lines in a coordinate plane.
- In the system \(2x + 5y = -4\) and \(3x - y = 11\), both equations are linear.
- These equations can be expressed in the form \(Ax + By = C\) which generally describes a line with slope and y-intercept.
Effective Algebra Problem Solving Using Substitution Method
The substitution method is an effective technique for solving a system of equations, especially when one equation can be easily solved for one of the variables. Let's delve deeper into how this method is applied.
By isolating \(y\) in the equation \(3x - y = 11\), we obtained \(y = 3x - 11\). This expression for \(y\) is then substituted into the other equation.
Here are the steps broken down:
By isolating \(y\) in the equation \(3x - y = 11\), we obtained \(y = 3x - 11\). This expression for \(y\) is then substituted into the other equation.
Here are the steps broken down:
- Isolate one variable: Choose an equation, like \(3x - y = 11\), and express \(y\) in terms of \(x\).
- Substitution: Replace \(y\) in the first equation \(2x + 5y = -4\) to have a single-variable equation \(2x + 5(3x - 11) = -4\).
- Solve for the first variable: Simplify and solve for \(x\), giving \(17x = 51\) which simplifies to \(x = 3\).
- Solve for the second variable: Substitute \(x = 3\) back into \(y = 3x - 11\) to find \(y = -2\).
- Verify: Ensure both values satisfy the original equations, safeguarding accurate solutions.
Other exercises in this chapter
Problem 13
Graph each inequality. $$x^{2}+y^{2} \leq 1$$
View solution Problem 13
In Exercises \(1-18,\) solve each system by the substitution method. $$ \left\\{\begin{array}{l} x y=3 \\ x^{2}+y^{2}=10 \end{array}\right. $$
View solution Problem 13
Solve each system. $$\left\\{\begin{aligned} 2 x+y &=2 \\ x+y-z &=4 \\ 3 x+2 y+z &=0 \end{aligned}\right.$$
View solution Problem 14
write the partial fraction decomposition of each rational expression. $$ \frac{9 x+21}{x^{2}+2 x-15} $$
View solution