Problem 13
Question
In each of Exercises \(13-30,\) calculate the derivative with respect to \(x\) of the given expression. \(\ln (4 x)\)
Step-by-Step Solution
Verified Answer
The derivative is \( \frac{1}{x} \).
1Step 1: Identify the Function
The given function is \(y = \ln(4x)\). This is a composite function where the natural logarithm function \(\ln(u)\) is applied to \(u = 4x\).
2Step 2: Use the Chain Rule
The derivative of a composite function, where \(y = \ln(u)\), is given by \(\frac{dy}{dx} = \frac{1}{u} \cdot \frac{du}{dx}\). First, find the derivative of the outer function \(\ln(u)\) with respect to \(u\); it is \(\frac{1}{u}\).
3Step 3: Differentiate the Inner Function
The inner function is \(u = 4x\). Differentiate it with respect to \(x\): \(\frac{du}{dx} = 4\).
4Step 4: Combine Using the Chain Rule
Substitute the derivatives from the previous steps into the chain rule formula: \[ \frac{dy}{dx} = \frac{1}{4x} \cdot 4 = \frac{4}{4x} \].
5Step 5: Simplify the Expression
Cancel common factors in the derivative expression: \(\frac{4}{4x} = \frac{1}{x}\). This is the derivative of the given function.
Key Concepts
Composite FunctionsNatural LogarithmChain Rule
Composite Functions
In mathematics, composite functions consist of two or more functions where the output of one function becomes the input of another. Understanding composite functions is crucial for learning how to apply the chain rule in calculus.
Consider the given function: \(y = \ln(4x)\). Notice here, \(\ln(u)\) is our outer function and represents the natural logarithm, while \(u = 4x\) is the inner function. This inner function acts as the argument for the logarithmic function. Composite functions provide a layered approach to problem-solving.
Consider the given function: \(y = \ln(4x)\). Notice here, \(\ln(u)\) is our outer function and represents the natural logarithm, while \(u = 4x\) is the inner function. This inner function acts as the argument for the logarithmic function. Composite functions provide a layered approach to problem-solving.
- Outer function: \(\ln(u)\)
- Inner function: \(u = 4x\)
Natural Logarithm
The natural logarithm, often written as \(\ln(x)\), usually refers to the logarithm to the base \(e\) (where \(e\) is approximately 2.71828). It is a fundamental mathematical function used extensively in calculus and scientific computations.
When differentiating functions involving natural logarithms, it is crucial to recognize the natural logarithm has a straightforward derivative formula:
When differentiating functions involving natural logarithms, it is crucial to recognize the natural logarithm has a straightforward derivative formula:
- Derivative of Natural Logarithm: \[\frac{d}{dx} (\ln(x)) = \frac{1}{x}\]
Chain Rule
The chain rule is a critical tool in calculus used for finding the derivative of composite functions. When a function is composed of another function, the chain rule provides a method to differentiate both layers to find the overall derivative.
In simpler terms, if you have a function \(y\) that is a composition of two functions \(f(g(x))\), with an outer function \(f\) and an inner function \(g\), the derivative is found by:
In simpler terms, if you have a function \(y\) that is a composition of two functions \(f(g(x))\), with an outer function \(f\) and an inner function \(g\), the derivative is found by:
- Taking the derivative of the outer function with respect to the inner function, denoted as \(f'(g(x))\).
- Multiplying the result by the derivative of the inner function, expressed as \(g'(x)\).
- Recognizing the derivative of \(\ln(u)\), which is \(\frac{1}{u}\),
- And the derivative of \(u = 4x\), which is \(4\).
Other exercises in this chapter
Problem 13
Use the method of substitution to calculate the indefinite integrals. $$ \int \frac{x}{\sqrt{1+x^{2}}} d x $$
View solution Problem 13
Suppose that \(\int_{2}^{1} f(x) d x=0\) and \(\int_{2}^{1} g(x) d x=0 .\) Evaluate \(\int_{2}^{1}(f(x)-3 g(x)+5) d x\).
View solution Problem 13
In Exercises \(11-20,\) calculate \(F(x)=\int_{a}^{x} f(t) d t\) $$ f(t)=4 t^{1 / 3} \quad a=8 $$
View solution Problem 13
In Exercises \(11-16,\) use summation notation to express the sum. $$ 9+13+17+21+25+29 $$
View solution