Problem 13
Question
In \(11-18, P\) is a point on the terminal side of an angle in standard position with measure \(\theta\) and on a circle with center at the origin and radius \(r .\) For each point \(P,\) find: a. \(r\) b. \(\csc \theta\) c. \(\sec \theta\) d. \(\cot \theta\) \((-3,-3)\)
Step-by-Step Solution
Verified Answer
\( r = 3\sqrt{2}, \csc \theta = -\sqrt{2}, \sec \theta = -\sqrt{2}, \cot \theta = 1 \).
1Step 1: Calculate the Radius, r
To find the radius \( r \) of the circle, we use the distance formula from the origin \( (0,0) \) to the point \( (-3, -3) \). This is given by \( r = \sqrt{(-3)^2 + (-3)^2} = \sqrt{9 + 9} = \sqrt{18} = 3\sqrt{2} \).
2Step 2: Determine the Sine, Cosine, and Tangent Values
The coordinates of the point \((-3, -3)\) give us \( x = -3 \) and \( y = -3 \). The sine and cosine of \( \theta \) are found using \( \sin \theta = \frac{y}{r} = \frac{-3}{3\sqrt{2}} = -\frac{\sqrt{2}}{2} \) and \( \cos \theta = \frac{x}{r} = \frac{-3}{3\sqrt{2}} = -\frac{\sqrt{2}}{2} \). The tangent is \( \tan \theta = \frac{y}{x} = \frac{-3}{-3} = 1 \).
3Step 3: Calculate the Cosecant, \( \csc \theta \)
The cosecant function is the reciprocal of sine. Thus, \( \csc \theta = \frac{1}{\sin \theta} = \frac{1}{-\frac{\sqrt{2}}{2}} = -\frac{2}{\sqrt{2}} = -\sqrt{2} \).
4Step 4: Calculate the Secant, \( \sec \theta \)
The secant function is the reciprocal of cosine. Thus, \( \sec \theta = \frac{1}{\cos \theta} = \frac{1}{-\frac{\sqrt{2}}{2}} = -\frac{2}{\sqrt{2}} = -\sqrt{2} \).
5Step 5: Calculate the Cotangent, \( \cot \theta \)
The cotangent function is the reciprocal of tangent. Thus, \( \cot \theta = \frac{1}{\tan \theta} = \frac{1}{1} = 1 \).
Key Concepts
CosecantSecantCotangent
Cosecant
The cosecant, abbreviated as \( \csc \theta \), is one of the three important reciprocal trigonometric functions. It's the reciprocal of the sine function. In simpler terms, if you know the sine of an angle, you can find its cosecant by flipping the fraction upside down.
### Practical Understanding of CosecantIf \( \sin \theta = \frac{y}{r} \), then \( \csc \theta = \frac{r}{y} \). For example, if \( \sin \theta = -\frac{\sqrt{2}}{2} \) as per the exercise, the cosecant will be:
Knowing \( \csc \theta \) can help when calculating lengths and angles in right-angled triangles, especially when other direct trigonometric values are not readily available.
### Practical Understanding of CosecantIf \( \sin \theta = \frac{y}{r} \), then \( \csc \theta = \frac{r}{y} \). For example, if \( \sin \theta = -\frac{\sqrt{2}}{2} \) as per the exercise, the cosecant will be:
- Flip the sine: \( \csc \theta = \frac{1}{-\frac{\sqrt{2}}{2}} = -\sqrt{2} \)
Knowing \( \csc \theta \) can help when calculating lengths and angles in right-angled triangles, especially when other direct trigonometric values are not readily available.
Secant
The secant function, denoted as \( \sec \theta \), is another reciprocal trigonometric function. It is the reciprocal of the cosine function. Just like the cosecant and sine relationship, secant is about reversing the cosine value.
### Practical Understanding of SecantFor \( \cos \theta = \frac{x}{r} \), the secant can be found as \( \sec \theta = \frac{r}{x} \). In our specific case from the exercise, since \( \cos \theta = -\frac{\sqrt{2}}{2} \), the calculation is:
It is often visualized on the unit circle where you see the length of the line segment from the origin to a point where the circle intersects a line parallel to the y-axis. Thus, it plays a critical role in understanding scenarios where angles and distances are directly related among circles and triangles.
### Practical Understanding of SecantFor \( \cos \theta = \frac{x}{r} \), the secant can be found as \( \sec \theta = \frac{r}{x} \). In our specific case from the exercise, since \( \cos \theta = -\frac{\sqrt{2}}{2} \), the calculation is:
- Flip the cosine: \( \sec \theta = \frac{1}{-\frac{\sqrt{2}}{2}} = -\sqrt{2} \)
It is often visualized on the unit circle where you see the length of the line segment from the origin to a point where the circle intersects a line parallel to the y-axis. Thus, it plays a critical role in understanding scenarios where angles and distances are directly related among circles and triangles.
Cotangent
Cotangent, abbreviated as \( \cot \theta \), is the reciprocal of the tangent function. This means it flips the roles of sine and cosine compared to tangent. Tangent is normally \( \tan \theta = \frac{y}{x} \), while the cotangent changes this to \( \cot \theta = \frac{x}{y} \).
### Solving for CotangentTaking the exercise example, where \( \tan \theta = 1 \), cotangent is straightforward:
It's often helpful in determining complementary angles and understanding the transition between different trigonometric ratios in various quadrants of the trigonometric circle.Understanding cotangent can greatly ease calculations, particularly in problems where angles are approaching 0 or \( \pi \), due to its relationships and properties with broader trigonometric identities.
### Solving for CotangentTaking the exercise example, where \( \tan \theta = 1 \), cotangent is straightforward:
- Flip the tangent: \( \cot \theta = \frac{1}{1} = 1 \)
It's often helpful in determining complementary angles and understanding the transition between different trigonometric ratios in various quadrants of the trigonometric circle.Understanding cotangent can greatly ease calculations, particularly in problems where angles are approaching 0 or \( \pi \), due to its relationships and properties with broader trigonometric identities.
Other exercises in this chapter
Problem 13
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In \(8-17,\) name the quadrant in which an angle of each given measure lies. $$ -200^{\circ} $$
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