Problem 13
Question
Graph each inequality. See Examples 1 and \(2 .\) $$ \frac{x^{2}}{4}+\frac{y^{2}}{9} \leq 1 $$
Step-by-Step Solution
Verified Answer
Graph an ellipse with center at origin and axes 2 and 3; shade inside including the boundary.
1Step 1: Identify the Inequality's Form
The inequality \( \frac{x^{2}}{4}+\frac{y^{2}}{9} \leq 1 \) is in the standard form of an ellipse. Specifically, it represents an ellipse centered at the origin \((0,0)\) with semi-major and semi-minor axes along the coordinate axes.
2Step 2: Determine the Axes Lengths
From the equation \( \frac{x^{2}}{4}+\frac{y^{2}}{9} = 1 \), we identify that the lengths of the semi-major and semi-minor axes are \( \sqrt{9} = 3 \) (along the y-axis) and \( \sqrt{4} = 2 \) (along the x-axis), respectively.
3Step 3: Sketch the Ellipse
Draw an ellipse centered at the origin \((0,0)\) going through the points \((2,0), (-2,0), (0,3), (0,-3)\), which are determined by the lengths of the semi-axes.
4Step 4: Graph the Inequality
Since the inequality is \( \leq \), shade the region inside the ellipse, including the boundary, because points inside satisfy the inequality. Use a solid line for the ellipse boundary to indicate the inclusion of points on the ellipse.
Key Concepts
Graphing InequalitiesEllipse EquationsStandard Form of an EllipseAxes Lengths
Graphing Inequalities
Graphing inequalities like \( \frac{x^{2}}{4}+\frac{y^{2}}{9} \leq 1 \) involves more than just plotting a curve or shape. It requires understanding how to not only draw the boundary of a shape but also determine which area it encompasses based on the inequality sign. In our equation,
- The symbol \( \leq \) indicates "less than or equal to."
- This means that we're looking for all the points that lie inside or exactly on the ellipse.
Ellipse Equations
An ellipse equation, such as \( \frac{x^{2}}{4}+\frac{y^{2}}{9} = 1 \), is crucial in visualizing and understanding the shape's geometry. Ellipses are unique, oval-shaped figures defined clearly by their mathematical equation. Key features of an ellipse equation include:
- The denominators, which determine the ellipse's width and height.
- The numerator always being \( x^{2} \) and \( y^{2} \) at the origin.
Standard Form of an Ellipse
The standard form of an ellipse provides a systematic way to write its equation. It looks like this: \( \frac{x^{2}}{a^{2}} + \frac{y^{2}}{b^{2}} = 1 \). The essence of this format is in its parts:
- \( a^2 \) and \( b^2 \) are the squares of the lengths of the semi-axes.
- The numerator \( x^2 \) and \( y^2 \) indicate the center is at the origin (\(0,0\)).
Axes Lengths
Axes lengths are fundamental in defining an ellipse’s size and shape. They are portrayed through the terms \( a \) and \( b \), representing half the lengths of the major and minor axes of the ellipse. To find them, you take the square roots of the denominators from the standard form equation:
- For the x-axis, you'd determine \( a \) from \( a^2 \); here, \( a^2 = 4 \) so \( a = 2 \).
- For the y-axis, \( b \) is from \( b^2 \); here, \( b^2 = 9 \) so \( b = 3 \).
Other exercises in this chapter
Problem 12
The graph of each equation is a parabola. Find the vertex of the parabola and then graph it. $$y=-2 x^{2}$$
View solution Problem 13
Solve each nonlinear system of equations for real solutions. $$ \left\\{\begin{aligned} y &=x^{2} \\ 3 x+y &=10 \end{aligned}\right. $$
View solution Problem 13
Sketch the graph of each equation. \(4 x^{2}+25 y^{2}=100\)
View solution Problem 13
The graph of each equation is a parabola. Find the vertex of the parabola and then graph it. $$x=(y-2)^{2}+3$$
View solution