Problem 13
Question
Graph each equation. Identify the conic section and describe the graph and its lines of symmetry. Then find the domain and range. $$ x^{2}+9 y^{2}=1 $$
Step-by-Step Solution
Verified Answer
The given equation represents a vertically oriented ellipse with a domain of \(-1 \leq x \leq 1\) and a range of \(-\frac{1}{3} \leq y \leq \frac{1}{3}\). The lines of symmetry are the lines x=0 and y=0.
1Step 1: Identifying the Conic Section
From the form of the equation \(x^{2}+9 y^{2}=1\), we recognize it as the standard equation of an ellipse with the form \(\frac{x^{2}}{a^2} + \frac{y^{2}}{b^2} = 1\). Whereas a and b are the semi major and semi minor axes respectively and here \(a^2 = 1\) and \(b^2 = \frac{1}{9}\). Therefore, the conic section in this problem is an ellipse.
2Step 2: Describing the Graph and Its Lines of Symmetry
Since 'a' is along x-axis and 'b' is along y-axis, hence, the ellipse stretches more along the y-axis than x-axis. This indicates that it is a vertically oriented ellipse. The lines of symmetry for an ellipse are its major and minor axes. In this case, lines of symmetry are x=0 and y=0.
3Step 3: Finding the Domain and Range
The domain (set of all x-values) and range (set of all y-values) can be read directly from the equation of the ellipse. The maximum x-value is 'a' and the minimum x-value is '-a', so the domain is \(-1 \leq x \leq 1\). The maximum y-value is 'b' and the minimum y-value is '-b', so the range is \(-\frac{1}{3} \leq y \leq \frac{1}{3}\).
Key Concepts
EllipsesLines of SymmetryDomain and RangeGraphing Equations
Ellipses
Ellipses are a type of conic section that appear as an elongated circle. Imagine stretching a circle until it looks more like an oval. In mathematical terms, ellipses are defined by the equation \( \frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 \). Here, \(a\) and \(b\) denote the lengths of the semi-axes. The larger value between \(a\) and \(b\) decides whether the ellipse stretches more along the x-axis or the y-axis. This can make the ellipse either wider or taller.
For the given equation \(x^{2}+9 y^{2}=1\), we identified it as an ellipse. By rewriting the equation in standard form, we see that \(a^2=1\) and \(b^2=\frac{1}{9}\). Thus, this ellipse is taller rather than wider, indicating that it is stretched along the y-axis.
Understanding ellipses is crucial because they model many real-world phenomena, such as planetary orbits.
For the given equation \(x^{2}+9 y^{2}=1\), we identified it as an ellipse. By rewriting the equation in standard form, we see that \(a^2=1\) and \(b^2=\frac{1}{9}\). Thus, this ellipse is taller rather than wider, indicating that it is stretched along the y-axis.
Understanding ellipses is crucial because they model many real-world phenomena, such as planetary orbits.
Lines of Symmetry
Lines of symmetry are imaginary lines that pass through an object or shape, creating a mirror-like reflection on either side. For ellipses, these lines simplify the complexities of the shape.
Ellipses have two lines of symmetry: the major and the minor axes. These axes are the longest and shortest diameters, respectively. For the equation \(x^{2}+9 y^{2}=1\), the lines of symmetry can be found at \(x=0\) and \(y=0\). These axes cut through the ellipse's center, reflecting the equal curves on either side.
Ellipses have two lines of symmetry: the major and the minor axes. These axes are the longest and shortest diameters, respectively. For the equation \(x^{2}+9 y^{2}=1\), the lines of symmetry can be found at \(x=0\) and \(y=0\). These axes cut through the ellipse's center, reflecting the equal curves on either side.
- Horizontal symmetry (along the x-axis) is where the top reflects to the bottom.
- Vertical symmetry (along the y-axis) reflects the left half to the right.
Domain and Range
In mathematics, the domain refers to all the possible x-values, while the range refers to all the possible y-values that a function can take. For conic sections like ellipses, these values define the shape's boundaries on a graph.
For the ellipse \(x^{2}+9 y^{2}=1\), observing the equation helps to identify the stretching limits on both axes:
For the ellipse \(x^{2}+9 y^{2}=1\), observing the equation helps to identify the stretching limits on both axes:
- The domain is restricted to \(-1 \leq x \leq 1\), as this reflects the farthest left and right the ellipse reaches.
- The range is \(-\frac{1}{3} \leq y \leq \frac{1}{3}\), found by calculating the limits of vertical stretching.
Graphing Equations
Graphing equations, especially for conic sections like ellipses, provides a visual representation of equations, helping in understanding the shape and orientation.
When graphing the equation \(x^{2}+9 y^{2}=1\), it is essential to ensure the re-formatted equation guides the plot:
When graphing the equation \(x^{2}+9 y^{2}=1\), it is essential to ensure the re-formatted equation guides the plot:
- Reform the equation to \(\frac{x^2}{1} + \frac{y^2}{(1/3)^2} = 1\).
- Recognize that the x-axis runs from -1 to 1, and the y-axis from -\(\frac{1}{3}\) to \(\frac{1}{3}\).
- Mark these onto the coordinate plane, then sketch the ellipse through these points, respecting the symmetry lines at \(x=0\) and \(y=0\).
Other exercises in this chapter
Problem 13
Find the foci of each hyperbola. Then draw the graph. $$ \frac{x^{2}}{64}-\frac{y^{2}}{36}=1 $$
View solution Problem 13
Write an equation of a parabola opening upward with a vertex at the origin. focus 1.5 units from vertex
View solution Problem 13
Write an equation for each translation. $$ x^{2}+y^{2}=100 ; \text { down } 5 $$
View solution Problem 14
Find an equation of an ellipse for each given height and width. Assume that the center of the ellipse is \((0,0) .\) $$ h=8 \mathrm{ft}, w=2 \mathrm{ft} $$
View solution