Problem 13
Question
For exercises 7-32, simplify. $$ \left(\frac{h^{2}}{h^{2}+3 h}\right)\left(\frac{h^{2}-9}{h}\right) $$
Step-by-Step Solution
Verified Answer
The simplified expression is \(h - 3\).
1Step 1: Factor the Expressions
Factor the denominators and numerators where possible. Notice that \(h^2 + 3h = h(h + 3)\) and \(h^2 - 9 = (h + 3)(h - 3)\).
2Step 2: Rewrite the Expression with the Factors
Substitute these factors back into the original expression: \ \( \frac{h^2}{h(h + 3)} \times \frac{(h + 3)(h - 3)}{h} \).
3Step 3: Simplify the Fractions
Simplify the fractions by canceling out common factors. The common factors \(h\) and \(h + 3\) appear in both the numerator and the denominator. This simplifies to: \ \( \frac{h \times h}{h \times (h + 3)} \times \frac{(h+3)(h-3)}{h} = \frac{h}{h + 3} \times (h - 3) \ = h - 3 \).
4Step 4: Final Simplified Form
The expression simplifies to \(h - 3\).
Key Concepts
Factoring ExpressionsCanceling Common FactorsSimplification of Fractions
Factoring Expressions
Factoring is a key technique in algebra that breaks down complex expressions into simpler factors. Think of it as finding the building blocks of a number or expression. To factor an expression like \(h^2 + 3h\), look for common elements. Here, both terms have a common factor of \(h\), giving us \(h(h + 3)\).
Similarly, the expression \(h^2 - 9\) is a difference of squares, which factors to \((h + 3)(h - 3)\). Factoring expressions makes it easier to simplify fractions, set equations to zero, and solve for variables.
Similarly, the expression \(h^2 - 9\) is a difference of squares, which factors to \((h + 3)(h - 3)\). Factoring expressions makes it easier to simplify fractions, set equations to zero, and solve for variables.
Canceling Common Factors
Once you've factored an expression, canceling common factors is the next step in simplification. Cancelling helps in reducing fractions by eliminating identical terms from the numerator and the denominator.
Take our example: after factoring, the expression is \( \frac{h^2}{h(h + 3)} \times \frac{(h + 3)(h - 3)}{h} \). Here, the common factors \(h\) and \(h + 3\) are present in both the numerator and the denominator. By canceling these out, the fraction becomes much simpler to work with.
Remember: you can only cancel terms that are multiplied together, not terms that are added or subtracted.
Take our example: after factoring, the expression is \( \frac{h^2}{h(h + 3)} \times \frac{(h + 3)(h - 3)}{h} \). Here, the common factors \(h\) and \(h + 3\) are present in both the numerator and the denominator. By canceling these out, the fraction becomes much simpler to work with.
Remember: you can only cancel terms that are multiplied together, not terms that are added or subtracted.
Simplification of Fractions
Simplifying fractions involves reducing them to their simplest form. This process often includes factoring and canceling common factors. For our example, after factoring and canceling, we're left with \( \frac{h \times h}{h \times (h + 3)} \times \frac{(h+3)(h-3)}{h} \), which simplifies to \( \frac{h}{h + 3} \times (h - 3) = h - 3 \).
Each step in simplification requires careful attention to detail to ensure accuracy. Double-check your work: one small mistake can throw off the whole solution. Simplifying fractions makes them easier to interpret and use in further calculations or real-world problems.
Each step in simplification requires careful attention to detail to ensure accuracy. Double-check your work: one small mistake can throw off the whole solution. Simplifying fractions makes them easier to interpret and use in further calculations or real-world problems.
Other exercises in this chapter
Problem 13
The relationship of \(x\) and \(y\) is an inverse variation. When \(x=2, y=10\). a. Find the constant of proportionality, \(k\). b. Write an equation that repre
View solution Problem 13
For exercises 13-24, rewrite each expression as an equivalent expression with the given denominator. $$ \frac{3}{7} ; 56 $$
View solution Problem 14
The relationship of \(x\) and \(y\) is an inverse variation. When \(x=4, y=5\). a. Find the constant of proportionality, \(k\). b. Write an equation that repres
View solution Problem 14
For exercises 11-30, (a) solve. (b) check. $$ \frac{13}{d}-\frac{5}{9}=\frac{1}{6} $$
View solution