Problem 13
Question
Find the \(x\) - and \(y\) -intercepts of the equation. $$2 x+3 y=12$$
Step-by-Step Solution
Verified Answer
The \(x\)-intercept is (6, 0) and the \(y\)-intercept is (0, 4).
1Step 1: Identify the equation
The given equation is \(2x + 3y = 12\). This is a linear equation in two variables.
2Step 2: Find the x-intercept
To find the \(x\)-intercept, set \(y = 0\) and solve for \(x\).\[2x + 3(0) = 12\]\[2x = 12\]\[x = 6\]So, the \(x\)-intercept is \( (6, 0) \).
3Step 3: Find the y-intercept
To find the \(y\)-intercept, set \(x = 0\) and solve for \(y\).\[2(0) + 3y = 12\]\[3y = 12\]\[y = 4\]So, the \(y\)-intercept is \( (0, 4) \).
Key Concepts
x-intercepty-interceptsolving linear equations
x-intercept
Understanding the x-intercept of a linear equation is easy and important. You are essentially finding the point where the line crosses the x-axis. At the x-intercept, the value of y is always 0.
To find the x-intercept for the given equation, follow these steps:
\[2x + 3(0) = 12\]
Solving this, we get:
\[2x = 12\]
\[x = 6\]
Therefore, the x-intercept is (6, 0). This tells you that at the point where the line crosses the x-axis, the x-coordinate is 6.
To find the x-intercept for the given equation, follow these steps:
- Set y to 0 in the equation.
- Solve the resulting equation for x.
\[2x + 3(0) = 12\]
Solving this, we get:
\[2x = 12\]
\[x = 6\]
Therefore, the x-intercept is (6, 0). This tells you that at the point where the line crosses the x-axis, the x-coordinate is 6.
y-intercept
The y-intercept is where the line crosses the y-axis. Here, the value of x is always 0. Finding the y-intercept involves a similar process to finding the x-intercept.
Follow these steps to find the y-intercept for any linear equation:
\[2(0) + 3y = 12\]
Simplify and solve for y:
\[3y = 12\]
\[y = 4\]
Therefore, the y-intercept is (0, 4). This means that the point where the line crosses the y-axis has a y-coordinate of 4.
Follow these steps to find the y-intercept for any linear equation:
- Set x to 0 in the equation.
- Solve the resulting equation for y.
\[2(0) + 3y = 12\]
Simplify and solve for y:
\[3y = 12\]
\[y = 4\]
Therefore, the y-intercept is (0, 4). This means that the point where the line crosses the y-axis has a y-coordinate of 4.
solving linear equations
Solving linear equations is a fundamental skill in algebra. A linear equation is any equation that can be written in the form \(Ax + By = C\), where A, B, and C are constants.
To solve a linear equation, you need to isolate the variable of interest. This often involves multiple steps:
To find the x-intercept, set y to 0.
This gives \[2x = 12\] then solving for x, \[x = 6\]
To find the y-intercept, set x to 0.
This gives \[3y = 12\] then solving for y, \[y = 4\]
Remember, the key steps include:
To solve a linear equation, you need to isolate the variable of interest. This often involves multiple steps:
- Combine like terms.
- Use addition or subtraction to move terms from one side of the equation to the other.
- Use multiplication or division to solve for the variable.
To find the x-intercept, set y to 0.
This gives \[2x = 12\] then solving for x, \[x = 6\]
To find the y-intercept, set x to 0.
This gives \[3y = 12\] then solving for y, \[y = 4\]
Remember, the key steps include:
- Substitute known values.
- Simplify to isolate the variable.
- Check your work by substituting the solution back into the original equation.
Other exercises in this chapter
Problem 12
Find the \(x\) - and \(y\) -intercepts of the equation. $$y+3 x=-6$$
View solution Problem 13
Write an equation of the line satisfying the given conditions. Passing through \((4,-2)\) with slope 1
View solution Problem 14
Write an equation of the line satisfying the given conditions. Passing through \((-3,2)\) with slope \(-1\)
View solution Problem 14
Find the slope of the line passing through the given points. Round to the nearest hundredth where necessary. \((3,-1)\) and \((3,2)\)
View solution