Problem 13
Question
Find the magnitude of the given vector. $$(3,5,-4)$$
Step-by-Step Solution
Verified Answer
\(5\sqrt{2} \approx 7.07\)
1Step 1: Apply the Magnitude Formula
\(\|\mathbf{v}\| = \sqrt{3^2 + 5^2 + (-4)^2} = \sqrt{9 + 25 + 16} = \sqrt{50} = 5\sqrt{2}\)
2Step 2: Approximate
\(5\sqrt{2} \approx 7.07\)
Key Concepts
vectorsmagnitude formulathree-dimensional vectors
vectors
Vectors are mathematical objects used to represent quantities that have both magnitude and direction.
Vectors are often visually depicted as arrows pointing in a certain direction, where the length of the arrow indicates the magnitude of the vector. In mathematics and physics, vectors are used to describe velocities, forces, and other directional quantities.
Vectors are often visually depicted as arrows pointing in a certain direction, where the length of the arrow indicates the magnitude of the vector. In mathematics and physics, vectors are used to describe velocities, forces, and other directional quantities.
- Components: A vector in space can be broken down into its components, typically represented as coordinates. For example, a vector can be written as \((x, y)\) in two-dimensional space or \((x, y, z)\) in three-dimensional space.
- Notation: Vectors are notated with boldface type or with an arrow above the letter, such as \( \vec{v} \) or v.
- Operations: Vectors can be added together, subtracted from one another, and multiplied by a scalar. Each of these operations has specific rules that respect the directional nature of vectors.
magnitude formula
The magnitude of a vector is a measure of its length. It tells you how "long" a vector is without regard to its direction. To compute the magnitude of a vector, we use a specific formula.
This formula is derived from extending the Pythagorean theorem to three dimensions, where \( x, y, \) and \( z \) are the respective components of the vector.
Magnitude Formula for Three-Dimensional Vectors
If you have a vector \( \vec{v} = (x, y, z) \), its magnitude \( |\vec{v}| \) is calculated by the formula:\[|\vec{v}| = \sqrt{x^2 + y^2 + z^2}\]This formula is derived from extending the Pythagorean theorem to three dimensions, where \( x, y, \) and \( z \) are the respective components of the vector.
- The squared values \( x^2, y^2, \) and \( z^2 \) ensure each component's contribution to the vector's magnitude is considered.
- The square root ensures the result is in the original units of the vector components, representing a distance.
three-dimensional vectors
Three-dimensional vectors extend the concept of vectors into space that includes length, width, and height. These vectors are crucial for modeling and understanding real-world situations where more complex spatial orientations are involved.
Defining Three-Dimensional Vectors
A three-dimensional vector \( \vec{v} \) can be expressed as \( (x, y, z) \), where:- \( x \): is the component along the x-axis (horizontal direction).
- \( y \): is the component along the y-axis (vertical direction).
- \( z \): is the component along the z-axis (depth direction).
Applications of Three-Dimensional Vectors
Three-dimensional vectors are widely used in various applications, including:- Physics: Describing forces, velocities, and other vector quantities in scenarios involving depth.
- Computer Graphics: Modeling scenes and transformations in 3D space.
- Engineering: Design and analysis of structures and systems in three-dimensional space.
Other exercises in this chapter
Problem 13
The lengths of two vectors a and \(b\) and the angle \(\theta\) between them are given. Find the length of their cross product, \(|\mathbf{a} \times \mathbf{b}|
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Find parametric equations for the line that passes through the points \(P\) and \(Q\) $$P(3,7,-5), \quad Q(7,3,-5)$$
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Find an equation of a sphere with the given radius \(r\) and center \(C\). $$r=\sqrt{6} ; \quad C(3,-1,0)$$
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Find \((a) u \cdot v\) and \((b)\) the angle between \(u\) and \(v\) to the nearest degree. $$\mathbf{u}=\mathbf{i}+3 \mathbf{j}, \quad \mathbf{v}=4 \mathbf{i}-
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