Problem 13
Question
Find the exact value of each expression. $$ \tan ^{-1} \frac{\sqrt{3}}{3} $$
Step-by-Step Solution
Verified Answer
The exact value of \( \tan^{-1}(\frac{\sqrt{3}}{3}) \) is \( 15^{\circ} \)
1Step 1: Identify the input of the inverse function
The input of inverse tangent function \(\tan^{-1}\), in this case, is \(\frac{\sqrt{3}}{3}\).
2Step 2: Simplify the input
The \(\sqrt{3}\) can be written as \(\sqrt{3}=\sqrt{2^2-1^2}=\sqrt{4-1}=\sqrt{3}\). Hence, the input of the inverse function is \(\frac{\sqrt{3}}{3} = \frac{\sqrt{3}}{3}\times\frac{2}{2}=\frac{2\sqrt{3}}{6}=\frac{\sqrt{3}}{3}\times 2\), which simplifies into \(\frac{2}{2\sqrt{3}}\).
3Step 3: Finding the angle
The procedure to find the corresponding angle involves finding a critical angle in the unit circle for which the tangent equals \(\frac{2}{2\sqrt{3}}\). Remembering that \(\tan(30^{\circ})=\frac{1}{\sqrt{3}}\), it can be observed that the input is half of this, which suggests that the corresponding angle should be half as well. Hence the angle is \(15^{\circ}\)
Key Concepts
Tangent FunctionUnit CircleAngle Measurement
Tangent Function
The tangent function, often abbreviated as tan, is one of the fundamental trigonometric functions. It relates the angle within a right triangle to the ratio of the opposite side over the adjacent side. For any given angle \( \theta \), the tangent can be mathematically expressed as:\[\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}\]Tangent has interesting properties when extended from a mere right triangle context into any angle measurement using the unit circle.
It is periodic and repeats its values every \( 180^\circ \) or \( \pi \) radians. Additionally, unlike sine and cosine that are defined for all real numbers, the tangent function has undefined values, where its denominator becomes zero (adjacent side equals zero).
These points occur at \( \frac{\pi}{2} + n\pi \), where \( n \) is an integer, making it crucial to manage these undefined areas in calculations, especially for inverse operations.
It is periodic and repeats its values every \( 180^\circ \) or \( \pi \) radians. Additionally, unlike sine and cosine that are defined for all real numbers, the tangent function has undefined values, where its denominator becomes zero (adjacent side equals zero).
These points occur at \( \frac{\pi}{2} + n\pi \), where \( n \) is an integer, making it crucial to manage these undefined areas in calculations, especially for inverse operations.
Unit Circle
A unit circle is a circle with a radius of one unit centered at the origin of a coordinate plane. The unit circle is a significant concept because it allows us to extend trigonometry to work with any angle. Every point on the unit circle corresponds to an angle formed by the positive x-axis and a line connecting the origin to the circle.
On the unit circle:
On the unit circle:
- The x-coordinate represents the cosine of the angle.
- The y-coordinate represents the sine of the angle.
- Tangent is derived from sine and cosine as \( \tan(\theta) = \frac{\sin(\theta)}{\cos(\theta)} \).
Angle Measurement
In trigonometry, angles can be measured in degrees or radians, and understanding both forms is fundamental. Degrees, which are more intuitive, divide a circle into 360 parts, while radians focus on the unit circle. A full circle in radians is \( 2\pi \), thus \( 180^\circ \) equals \( \pi \) radians.When utilizing inverse trigonometric functions such as \( \tan^{-1} \), it's important to convert the outputs between radians and degrees for wider applicability:
- \( 30^\circ \) converts to \( \frac{\pi}{6} \) radians.
- \( 15^\circ \) converts to \( \frac{\pi}{12} \) radians.
Other exercises in this chapter
Problem 12
Use the given triangles to evaluate each expression. If necessary, express the value without a square root in the denominator by rationalizing the denominator.
View solution Problem 12
evaluate the trigonometric function at the quadrantal angle, or state that the expression is undefined. $$ \csc \pi $$
View solution Problem 13
Determine the amplitude and period of each function. Then graph one period of the function. $$y=-3 \sin 2 \pi x$$
View solution Problem 13
Use the given triangles to evaluate each expression. If necessary, express the value without a square root in the denominator by rationalizing the denominator.
View solution