Problem 13
Question
Find the equation of the circle satisfying the given conditions. Center \((2,-1)\), goes through \((5,3)\)
Step-by-Step Solution
Verified Answer
The circle's equation is \((x - 2)^2 + (y + 1)^2 = 25\).
1Step 1: Recall the Standard Form of a Circle's Equation
The standard form of a circle's equation is \((x - h)^2 + (y - k)^2 = r^2\), where \((h, k)\) is the center and \(r\) is the radius.
2Step 2: Identify the Center of the Circle
We are given that the center of the circle is \((2, -1)\). So, \(h = 2\) and \(k = -1\).
3Step 3: Use the Distance Formula to Find the Radius
We find the radius by calculating the distance between the center \((2, -1)\) and the point \((5, 3)\) which lies on the circle. The distance formula is: \(r = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\).Substitute the values: \[r = \sqrt{(5 - 2)^2 + (3 - (-1))^2} = \sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5\]
4Step 4: Substitute the Center and Radius into the Circle's Equation
Now that we have \(h = 2\), \(k = -1\), and \(r = 5\), substitute these into the standard form \((x - h)^2 + (y - k)^2 = r^2\):\[(x - 2)^2 + (y + 1)^2 = 25\]
Key Concepts
Distance FormulaCenter of a CircleEquation of a CircleGeometry
Distance Formula
The distance formula is an essential tool in geometry for finding the distance between two points in a coordinate plane. This formula is particularly useful when working with circles to determine the radius. The distance formula is mathematically expressed as:\[ r = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}\] Here,
- \((x_1, y_1)\) and \((x_2, y_2)\) are the coordinates of the two points.
- \(r\) represents the distance or radius in the case of a circle.
Center of a Circle
The center of a circle is the fixed point from which all points on the circle are equidistant. Knowing the center is critical when you need to formulate the equation of a circle in its standard format.In the context of a circle's equation, the center is denoted by the coordinates \((h, k)\). This pair of numbers plays a vital role as they help define the location of the circle on a graph.
- In the problem statement, the center of the circle is \((2, -1)\).
- This means that every point on the circle is exactly the radius distance of 5 units from \((2, -1)\).
Equation of a Circle
The equation of a circle is one of the fundamental concepts in geometry that ties together the center and radius. This equation allows us to represent the circle mathematically in a coordinate plane.The standard form of a circle's equation is expressed as:\[ (x - h)^2 + (y - k)^2 = r^2\]Where
- \((h, k)\) is the center of the circle.
- \(r\) is the radius.
Geometry
Geometry is a branch of mathematics concerned with the properties and relations of points, lines, surfaces, and solids. Understanding the geometry of circles specifically includes knowing how they are defined and how their properties interact.
Circles are a fundamental element in geometry, merging numbers with graphical representation. When exploring the geometry of a circle, we typically deal with:
- Radius - the distance from the circle's center to any point on the perimeter.
- Diameter - twice the length of the radius.
- Circumference - the total distance around the circle.
Other exercises in this chapter
Problem 13
Find the natural domain for each of the following. (a) \(F(z)=\sqrt{2 z+3}\) (b) \(g(v)=1 /(4 v-1)\) (c) \(\psi(x)=\sqrt{x^{2}-9}\) (d) \(H(y)=-\sqrt{625-y^{4}}
View solution Problem 13
, plot the graph of each equation. Begin by checking for symmetries and be sure to find all \(x\) - and \(y\) -intercepts.. $$ x^{2}-y^{2}=4 $$
View solution Problem 13
Express the solution set of the given inequality in interval notation and sketch its graph. $$ 2 x^{2}+5 x-3>0 $$
View solution Problem 13
simplify as much as possible. Be sure to remove all parentheses and reduce all fractions. $$ 1-\frac{1}{1+\frac{1}{2}} $$
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