Problem 13
Question
Find the derivative of the function. $$ f(t)=-3 t^{2}+2 t-4 $$
Step-by-Step Solution
Verified Answer
The derivative of the function \(f(t) = -3t^2 + 2t - 4\) is \(f'(t) = -6t + 2\).
1Step 1: Identify the Terms and Power Rule
The function given is a second-degree polynomial function, \(f(t) = -3t^2 + 2t - 4\). According to the Power Rule; the derivative of a function of the form \(t^n\) is given by \(n*t^{n-1}\). In this case, the power rule will be applied separately to each term in the function.
2Step 2: Apply the Power Rule to Each Term
Apply the power rule to each term. For the first term, \( -3t^2 \), the power rule gives us \( -3*2*t^{2-1}\), which simplifies to \( -6t \). For the second term, \( 2t \), the power rule gives us \( 2*1*t^{1-1} = 2 \). The last term \( -4 \) is a constant and its derivative is zero.
3Step 3: Combine the Derivatives
The derivatives found from each term in the function are combined to give the derivative of the entire function. This results in \(f'(t) = -6t + 2 + 0\), which simplifies to \(f'(t) = -6t + 2\).
Other exercises in this chapter
Problem 13
Find \(d y / d u, d u / d x\), and \(d y / d x\). $$ y=u^{2 / 3}, u=5 x^{4}-2 x $$
View solution Problem 13
Find the value of the derivative of the function at the given point. State which differentiation rule you used to find the derivative. $$ g(x)=\frac{2 x+1}{x-5}
View solution Problem 13
Describe the interval(s) on which the function is continuous. Explain why the function is continuous on the interval(s). If the function has a discontinuity, id
View solution Problem 13
Find the limit of (a) \(f(x)+g(x)\), (b) \(f(x) g(x)\), and (c) \(f(x) / g(x)\), as \(x\) approaches \(c\). $$ \begin{aligned} &\lim _{x \rightarrow c} f(x)=3 \
View solution