Problem 13
Question
Find each square root. Assume that all variables represent nonnegative real numbers. $$ -\sqrt{36} $$
Step-by-Step Solution
Verified Answer
The square root is -6.
1Step 1: Identify the Expression
The expression given is \(-\sqrt{36}\). Here, the negative sign is outside the square root.
2Step 2: Find the Square Root of 36
Calculate the square root of 36. Since 36 is a perfect square, we have: \(\sqrt{36} = 6\).
3Step 3: Apply the Negative Sign
Attach the negative sign to the result from Step 2. So, \(-\sqrt{36} = -6\).
4Step 4: Conclusion
Therefore, the solution to the problem \(-\sqrt{36}\) is \(-6\).
Key Concepts
Nonnegative Real NumbersPerfect SquaresNegative Sign in Square Roots
Nonnegative Real Numbers
In mathematics, nonnegative real numbers include all the positive real numbers and zero. These numbers are vital when dealing with square roots, as the square root operation is usually defined for nonnegative numbers only. The nonnegative real numbers are represented by the set
- This set encompasses all real numbers that are greater than or equal to zero.
- It helps in avoiding complex numbers in most basic calculations related to square roots.
Perfect Squares
Perfect squares are integers that are the square of an integer. Understanding perfect squares is essential when solving problems involving square roots, as they simplify calculations.
- For example, 36 is a perfect square because it is the result of squaring 6 (i.e., \(6^2 = 36\)).
- Working with perfect squares is straightforward because the square root of a perfect square is always an integer.
Negative Sign in Square Roots
The negative sign in front of a square root notation can sometimes be confusing, but it has a straightforward meaning. When you see a negative sign before the square root symbol, such as \(-\sqrt{36}\), it means you take the negative of the square root's result. For example:
- First, determine the square root: \(\sqrt{36} = 6\).
- Then apply the negative sign, \(-\sqrt{36} = -6\).
Other exercises in this chapter
Problem 13
Solve. $$ \sqrt[3]{x-2}-3=0 $$
View solution Problem 13
Rationalize each denominator. Assume that all variables represent positive real numbers. \(\frac{3}{\sqrt[3]{2}}\)
View solution Problem 13
Use radical notation to rewrite each expression. Simplify if possible. $$ (-27)^{1 / 3} $$
View solution Problem 13
Add or subtract as indicated. Assume that all variables represent positive real numbers. $$ \sqrt[3]{\frac{11}{8}}-\frac{\sqrt[3]{11}}{6} $$
View solution