Problem 13
Question
Find each indicated product. Remember the shortcut for multiplying binomials and the other special patterns we discussed in this section. $$(x+6)(x+10)$$
Step-by-Step Solution
Verified Answer
The product is \(x^2 + 16x + 60\).
1Step 1: Identify the Binomials
The problem involves multiplying two binomials: \((x + 6)\) and \((x + 10)\). We will use the distributive property (FOIL method) to find the product.
2Step 2: Apply First Terms Multiplication
Multiply the first terms of each binomial: \(x \times x = x^2\).
3Step 3: Apply Outer Terms Multiplication
Multiply the outer terms: \(x \times 10 = 10x\).
4Step 4: Apply Inner Terms Multiplication
Multiply the inner terms: \(6 \times x = 6x\).
5Step 5: Apply Last Terms Multiplication
Multiply the last terms: \(6 \times 10 = 60\).
6Step 6: Combine Like Terms
Now, combine the results from the FOIL method: \(x^2 + 10x + 6x + 60\). Combine the like terms \(10x\) and \(6x\) to get \(16x\).
7Step 7: Write the Final Expression
The product of the binomials \((x + 6)(x + 10)\) is \(x^2 + 16x + 60\).
Key Concepts
Distributive PropertyFOIL MethodLike TermsBinomialsAlgebraic Expressions
Distributive Property
The distributive property is a valuable tool in algebra, particularly when multiplying expressions. In the context of binomials, the distributive property tells us that every term in the first binomial should be multiplied by every term in the second binomial.
Think of it as spreading one binomial across the other. In \((x+6)(x+10)\), you distribute and multiply throughout so that nothing gets left behind.
Think of it as spreading one binomial across the other. In \((x+6)(x+10)\), you distribute and multiply throughout so that nothing gets left behind.
- Start with the first term in the first binomial: multiply it to each term in the second binomial.
- Next, take the second term in the first binomial and repeat the process.
FOIL Method
The FOIL method is a mnemonic that stands for First, Outer, Inner, Last. It is specifically designed to make multiplying two binomials straightforward.
Here's how each part of FOIL breaks down:
Here's how each part of FOIL breaks down:
- **First:** Multiply the first terms: \(x \times x = x^2\).
- **Outer:** Multiply the outer terms: \(x \times 10 = 10x\).
- **Inner:** Multiply the inner terms: \(6 \times x = 6x\).
- **Last:** Multiply the last terms: \(6 \times 10 = 60\).
Like Terms
Like terms are terms within an algebraic expression that have the same variable raised to the same power. When we multiply binomials and use the FOIL method, we often result in like terms, especially when dealing with linear expressions.
In the expression \(x^2 + 10x + 6x + 60\), the terms \(10x\) and \(6x\) are like terms because they both contain the variable \(x\) to the same degree (first degree).
Combining like terms is simple:
In the expression \(x^2 + 10x + 6x + 60\), the terms \(10x\) and \(6x\) are like terms because they both contain the variable \(x\) to the same degree (first degree).
Combining like terms is simple:
- Add or subtract the coefficients of like terms while keeping the variable part the same.
- For example, \(10x + 6x\) combines to \(16x\).
Binomials
A binomial is a polynomial with exactly two terms. Binomials are a fundamental component of algebraic expressions and are often seen when solving equations or multiplying expressions.
In the exercise \((x+6)(x+10)\), each bracket contains a binomial: two terms connected by either addition or subtraction.
When dealing with binomials, there are some key points to remember:
In the exercise \((x+6)(x+10)\), each bracket contains a binomial: two terms connected by either addition or subtraction.
When dealing with binomials, there are some key points to remember:
- Each term in a binomial can be a number, a variable, or the product of numbers and variables.
- In multiplication, they often follow specific patterns, like the one we've seen with the FOIL method.
Algebraic Expressions
Algebraic expressions are combinations of numbers and variables linked by operation symbols like addition, subtraction, multiplication, and division. They form the building blocks of algebraic equations and functions.
An algebraic expression can consist of:
Breaking down such expressions into steps simplifies the solving process, revealing the underlying mathematical structure.
An algebraic expression can consist of:
- Numbers (constants).
- Variables (like \(x, y, z\)) that hold values yet to be determined.
- Operations (+, −, ×, ÷).
Breaking down such expressions into steps simplifies the solving process, revealing the underlying mathematical structure.
Other exercises in this chapter
Problem 13
Use the difference-of-squares pattern to factor each of the following. $$(x+2)^{2}-y^{2}$$
View solution Problem 13
Factor each of the composite numbers into the product of prime numbers. For example, \(30=2 \cdot 3 \cdot 5 .\) $$44$$
View solution Problem 13
Find each product. $$\left(m^{2} n\right)\left(-m n^{2}\right)$$
View solution Problem 13
Add the given polynomials. \(-5 t-4\) and \(-6 t+9\)
View solution