Problem 13
Question
Express the vector with initial point \(P\) and terminal point \(Q\) in component form. $$P(3,2), \quad Q(8,9)$$
Step-by-Step Solution
Verified Answer
The vector in component form is \( \langle 5, 7 \rangle \).
1Step 1: Understand the Problem
We need to express the vector that starts at point \( P(3,2) \) and ends at point \( Q(8,9) \) in component form. A vector in component form is written as \( \langle x_2 - x_1, y_2 - y_1 \rangle \), where \( (x_1, y_1) \) are the coordinates of the initial point and \( (x_2, y_2) \) are the coordinates of the terminal point.
2Step 2: Identify Initial and Terminal Points
The coordinates of the initial point \( P \) are \( (3, 2) \), and the coordinates of the terminal point \( Q \) are \( (8, 9) \).
3Step 3: Calculate the Differences
Find the difference between the corresponding coordinates of the terminal point \( Q \) and the initial point \( P \): \[ x_2 - x_1 = 8 - 3 = 5 \]\[ y_2 - y_1 = 9 - 2 = 7 \]
4Step 4: Write the Component Form of the Vector
The component form of the vector is the pair \( \langle x_2 - x_1, y_2 - y_1 \rangle \). Using our calculated differences, the vector is \( \langle 5, 7 \rangle \).
Key Concepts
Initial PointTerminal PointCoordinate DifferencesComponent Vector Calculation
Initial Point
In the context of vectors, an **initial point** is where a vector begins. It's the starting coordinate that helps us understand where a vector originates. For instance, if a vector describes a journey, the initial point is like your starting point on a map.
When given in a coordinate plane, as in this exercise, the initial point is described by its
In our exercise, the initial point is \( P(3, 2) \). This means the vector starts at the coordinate where x is 3 and y is 2.
When given in a coordinate plane, as in this exercise, the initial point is described by its
- x-coordinate
- y-coordinate
In our exercise, the initial point is \( P(3, 2) \). This means the vector starts at the coordinate where x is 3 and y is 2.
Terminal Point
A **terminal point** is where a vector finishes, essentially acting as the endpoint. It represents the final position in the journey depicted by the vector.
Much like the initial point, it is denoted by an ordered pair, \( Q(x_2, y_2) \), which marks its position on the coordinate plane.
For our exercise, the terminal point is \( Q(8, 9) \). This tells us that the vector ends where x equals 8 and y equals 9.
Much like the initial point, it is denoted by an ordered pair, \( Q(x_2, y_2) \), which marks its position on the coordinate plane.
For our exercise, the terminal point is \( Q(8, 9) \). This tells us that the vector ends where x equals 8 and y equals 9.
Coordinate Differences
Understanding the **coordinate differences** between the terminal and initial points is crucial for finding a vector's component form. The differences tell us how far the vector has moved from its start to end point in each direction.
For any vector, these differences are calculated as:
In our scenario:
For any vector, these differences are calculated as:
- The difference in x-coordinates: \( x_2 - x_1 \)
- The difference in y-coordinates: \( y_2 - y_1 \)
In our scenario:
- The x-coordinate difference is \( 8 - 3 = 5 \)
- The y-coordinate difference is \( 9 - 2 = 7 \)
Component Vector Calculation
Once the coordinate differences are found, we can express the vector in **component form**. This form clearly illustrates the movement from the initial to the terminal point and is typically written as \( \langle x_2 - x_1, y_2 - y_1 \rangle \).
In component form, each value inside the brackets signifies the vector's movement
Understanding component form is essential in mathematics and physics, as it breaks down a vector into its primary directions, making it easier to analyze and apply in various problems.
In component form, each value inside the brackets signifies the vector's movement
- The first value for the x-axis
- The second value for the y-axis
Understanding component form is essential in mathematics and physics, as it breaks down a vector into its primary directions, making it easier to analyze and apply in various problems.
Other exercises in this chapter
Problem 13
Find an equation of a sphere with the given radius \(r\) and center \(C\). $$r=\sqrt{6} ; \quad C(3,-1,0)$$
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Find \((a) u \cdot v\) and \((b)\) the angle between \(u\) and \(v\) to the nearest degree. $$\mathbf{u}=\mathbf{i}+3 \mathbf{j}, \quad \mathbf{v}=4 \mathbf{i}-
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The lengths of two vectors a and \(b\) and the angle \(\theta\) between them are given. Find the length of their cross product, \(|\mathbf{a} \times \mathbf{b}|
View solution Problem 14
Find parametric equations for the line that passes through the points \(P\) and \(Q\) $$P(12,16,18), \quad Q(12,-6,0)$$
View solution