Problem 13
Question
Exer. 1-50: Solve the equation. $$ \sqrt{7-5 x}=8 $$
Step-by-Step Solution
Verified Answer
The solution is \(x = -\frac{57}{5}\).
1Step 1: Remove the Square Root
To eliminate the square root, square both sides of the equation. This means we take the expression under the square root, \(7-5x\), and square the right side, \(8\), as well. The equation becomes: \[(\sqrt{7 - 5x})^2 = 8^2\] Simplifying, this gives:\[7 - 5x = 64\]
2Step 2: Isolate the Variable Term
Next, to solve for \(x\), begin by isolating the term containing \(x\). Subtract 7 from both sides of the equation:\[7 - 5x - 7 = 64 - 7\]Simplifying gives:\[-5x = 57\]
3Step 3: Solve for x
Finally, to solve for \(x\), divide both sides of the equation by -5:\[-5x / -5 = 57 / -5\]Simplifying results in:\[x = -\frac{57}{5}\]
Key Concepts
Square RootsEquation Solving ProcessVariable Isolation
Square Roots
When looking at the equation \( \sqrt{7 - 5x} = 8 \), the square root symbol is crucial to understand. A square root asks, "What number multiplied by itself gives this number?" In this equation, we have \( \sqrt{7 - 5x} \), which means we are looking for a number that, when squared, equals \( 7 - 5x \).
To simplify or eliminate a square root, you can square both sides of the equation. Squaring "undoes" the square root, effectively removing it. This process transforms the equation. For example:
To simplify or eliminate a square root, you can square both sides of the equation. Squaring "undoes" the square root, effectively removing it. This process transforms the equation. For example:
- Original equation: \( \sqrt{7 - 5x} = 8 \)
- Squaring both sides: \((\sqrt{7 - 5x})^2 = 8^2\)
- This gives: \(7 - 5x = 64\)
Equation Solving Process
Solving an equation is like solving a puzzle, where each step brings you closer to the solution. It's essential to approach it systematically.
Here's a brief guide to the equation solving process:
Here's a brief guide to the equation solving process:
- Identify the operation: Recognize operations used in the equation (e.g., addition, multiplication, square roots). This helps in determining what steps will "undo" those operations.
- Apply the inverse operation: To cancel square roots, squares, etc., use inverse operations. For square roots, squaring is the inverse operation.
- Simplify: After applying inverse operations, simplify the equation to make it more manageable.
Variable Isolation
Variable isolation means getting the variable by itself on one side of the equation. This helps to find its value easily.
In our example, the term with \( x \) is \( -5x \). Here's how we isolated \( x \):
In our example, the term with \( x \) is \( -5x \). Here's how we isolated \( x \):
- Subtract: We started with \( 7 - 5x = 64 \). By subtracting 7 from both sides, we eliminated the 7 on the left. This results in \( -5x = 57 \).
- Divide: Next, we needed to undo the multiplication by -5. So, we divided both sides by -5: \( x = -\frac{57}{5} \).
Other exercises in this chapter
Problem 13
Exer. 1-40: Solve the inequality, and express the solutions in terms of intervals whenever possible. $$ x^{2}
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Exer. 13-20: Express the interval as an inequality in the variable \(x\). $$ (-5,8] $$
View solution Problem 13
Exer. 1-34: Write the expression in the form \(a+b i\), where \(a\) and \(b\) are real numbers. $$ (3+4 i)(3-4 i) $$
View solution Problem 13
Exer. 1-14: Solve the equation by factoring. $$ \frac{5 x}{x-3}+\frac{4}{x+3}=\frac{90}{x^{2}-9} $$
View solution