Problem 13
Question
Evaluate each expression for \(x=6 .\) See Example 1. $$ \frac{x^{2}-4 x-12}{x^{2}+x-2} $$
Step-by-Step Solution
Verified Answer
The value of the expression for \(x=6\) is 0.
1Step 1: Substitute the Value of x
Given the expression, first substitute the value of \(x = 6\). So the expression \( \frac{x^{2}-4x-12}{x^{2}+x-2} \) becomes \( \frac{6^{2}-4(6)-12}{6^{2}+6-2} \).
2Step 2: Simplify the Numerator
Simplify the numerator by calculating each term: \(6^{2} = 36\), \(-4(6) = -24\), and then subtract 12. Therefore, the numerator is \(36 - 24 - 12 = 0\).
3Step 3: Simplify the Denominator
Simplify the denominator by calculating each term: \(6^{2} = 36\), add 6, and subtract 2. Therefore, the denominator is \(36 + 6 - 2 = 40\).
4Step 4: Evaluate the Fraction
Substitute the simplified numerator and denominator back into the fraction. Since the numerator is 0, the entire expression simplifies to \(\frac{0}{40} = 0\).
Key Concepts
Expression EvaluationSubstitution MethodSimplification Process
Expression Evaluation
Expression evaluation involves finding the value of an algebraic expression after substituting numerical values for its variables. In our exercise, we have an algebraic fraction \[ \frac{x^{2}-4x-12}{x^{2}+x-2}. \]To evaluate this expression for a specific value of \(x\), in this case, \(x=6\), follow these steps:
- Substitute the given value into the expression.
- Perform arithmetic operations carefully.
- Ensure that each operation follows the correct order: powers, multiplication/division, and then addition/subtraction.
Substitution Method
The substitution method is a technique used to replace variables with their given numerical values in an expression. This process makes abstract algebraic expressions concrete and manageable.Here’s how it works using our exercise. Substitute \(x=6\) directly into the expression:\[\frac{6^{2} - 4(6) - 12}{6^{2} + 6 - 2}.\]Remember:
- Carefully replace each occurrence of \(x\) in the expression with the value 6.
- Pay attention to signs and operations while substituting, to prevent errors.
- After substitution, proceed to simplify each part (numerator and denominator separately).
Simplification Process
Once you've substituted a numerical value into an algebraic expression, the next step is simplification. Simplification helps in reducing an expression to its simplest form, making it easier to interpret the result.In our exercise:**Simplifying the Numerator**- Calculate \(6^{2} = 36\) then subtract \(-4 \times 6 = -24\) and finally subtract \(12\).- This results in \(36 - 24 - 12 = 0\).**Simplifying the Denominator**- Calculate \(6^{2} = 36\) then add \(6\) and subtract \(2\).- The result is \(36 + 6 - 2 = 40\).**Final Expression**- Substitute these simplified results back into the fraction \(\frac{0}{40}\), which yields \(0\).Simplification ensures that you arrive at a neat and easily interpretable answer, avoiding mistakes and ensuring consistency in your calculations.
Other exercises in this chapter
Problem 13
Simplify each complex fraction. See Example \(1 .\) $$ \frac{\frac{x}{y}}{\frac{1}{x}} $$
View solution Problem 13
Solve each of these number problems. See Example \(1 .\) If the same number is added to both the numerator and the denominator of \(\frac{2}{5},\) the result is
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Add and simplify the result, if possible. \(\frac{9}{x}+\frac{2}{x}\)
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Multiply, and then simplify, if possible. \(\frac{y+2}{y} \cdot \frac{3}{y^{2}}\)
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