Problem 13
Question
Divide. Divide \(10 b^{3}-8 b^{2}-5 b\) by \(-2 b\)
Step-by-Step Solution
Verified Answer
The result is \(-5b^{2} + 4b + \frac{5}{2}\)
1Step 1: Divide the first term
Start by dividing the first term of the polynomial, which is \(10b^{3}\), by \(-2b\). This gives us \(-5b^{2}\).
2Step 2: Divide the second term
Next, divide the second term, which is \(-8b^{2}\), by \(-2b\). This gives us \(4b\).
3Step 3: Divide the third term
Lastly, divide the third term, \(-5b\), by \(-2b\). This gives us \(2.5\) or \( \frac{5}{2}\).
Key Concepts
Monomial DivisionNegative CoefficientExponents
Monomial Division
When dividing one polynomial by another, especially with a monomial, the process is quite straightforward. A monomial is a polynomial with a single term. In our exercise,
- the polynomial is made up of multiple terms: \(10b^3 - 8b^2 - 5b\).
- The monomial divisor is \(-2b\).
Negative Coefficient
Dealing with negative coefficients can sometimes be tricky, but understanding them can simplify your division process. A coefficient is the number that multiplies a variable in a term. In division, signs play an essential role.When you divide two numbers with like signs, their quotient is positive. Likewise, dividing two numbers with unlike signs results in a negative quotient. In our example, the monomial \(-2b\) has both a negative sign and a coefficient of \(-2\). Therefore:
- Dividing \(10b^3\) by \(-2b\) gives \(-5b^2\) since the signs are opposite.
- Dividing \(-8b^2\) by \(-2b\) gives \(4b\), with identical signs resulting in a positive outcome.
- For \(-5b\) divided by \(-2b\), the negative signs cancel out, and the result is a positive \(2.5\) or \(\frac{5}{2}\).
Exponents
Exponents are a way to denote repeated multiplication of a number by itself. In polynomial division, understanding how to handle exponents is crucial.When dividing terms with the same base, you subtract the exponents. For instance, if you have \(b^m\) divided by \(b^n\), you apply the rule: \[b^m \div b^n = b^{m-n}\]In our exercise:
- The first term \(10b^3\) divided by \(-2b\) leads to \(-5b^{3-1} = -5b^2\)
- The second term \(-8b^2\) divided by \(-2b\) becomes \(4b^{2-1} = 4b\)
- The last term \(-5b\) divided by \(-2b\) simplifies to a constant because \(b^{1-1} = b^0 = 1\)
Other exercises in this chapter
Problem 13
Solve the proportion. Check for extraneous solutions. $$\frac{t-2}{t}=\frac{2}{t+3}$$
View solution Problem 13
Simplify the expression if possible. $$\frac{3 x^{2}-18 x}{-9 x^{2}}$$
View solution Problem 13
Solve the percent problem. What number is \(25 \%\) of \(80 ?\)
View solution Problem 13
Simplify the expression. $$\frac{9 x^{2}}{4} \cdot \frac{8}{18 x}$$
View solution