Problem 13
Question
Determine whether the graph of each quadratic function opens upward or downward. $$f(x)=x^{2}+5$$
Step-by-Step Solution
Verified Answer
The graph opens upward because \( a = 1 \) is positive.
1Step 1: Identify the general form of a quadratic function
A quadratic function is generally written in the form \( f(x) = ax^2 + bx + c \).
2Step 2: Recognize the given quadratic function
The given function is \( f(x) = x^2 + 5 \). Comparing this with the general form, it is seen that \( a = 1, b = 0, \text{and} c = 5 \).
3Step 3: Determine the direction the parabola opens
The value of \( a \) determines the direction the graph of the quadratic function opens. If \( a > 0 \), the parabola opens upward. If \( a < 0 \), the parabola opens downward. In this case, \( a = 1 \).
4Step 4: Conclude the direction
Since \( a = 1 \) is positive, the graph of the quadratic function \( f(x) = x^2 + 5 \) opens upward.
Key Concepts
Parabola DirectionQuadratic FormulaGraph Analysis
Parabola Direction
Understanding whether a parabola opens upward or downward is essential when dealing with quadratic functions.
The general form of a quadratic function is given by:
\( f(x) = ax^2 + bx + c \)
The key to determining the direction of the parabola lies in the coefficient \( a \) (the term in front of \( x^2 \)). This coefficient tells us:
For example, let’s consider the given quadratic function: \( f(x) = x^2 + 5 \). Here, the coefficient \( a \) is 1, which is positive.
Since \( a = 1 \) is a positive number, the graph of the function \( f(x) = x^2 + 5 \) opens upward.
Knowing this helps to predict the general shape of the graph without even plotting it.
The general form of a quadratic function is given by:
\( f(x) = ax^2 + bx + c \)
The key to determining the direction of the parabola lies in the coefficient \( a \) (the term in front of \( x^2 \)). This coefficient tells us:
- - If \( a > 0 \), the parabola opens upward.
- If \( a < 0 \), the parabola opens downward.
For example, let’s consider the given quadratic function: \( f(x) = x^2 + 5 \). Here, the coefficient \( a \) is 1, which is positive.
Since \( a = 1 \) is a positive number, the graph of the function \( f(x) = x^2 + 5 \) opens upward.
Knowing this helps to predict the general shape of the graph without even plotting it.
Quadratic Formula
The quadratic formula is a crucial tool for solving quadratic equations. It is derived from the general form of a quadratic function:
\( ax^2 + bx + c = 0 \).
The formula helps to find the roots (or solutions) of the quadratic equation and is expressed as:
\[ x = \frac{-b \, \pm \, \sqrt{b^2 - 4ac}}{2a} \]
Here’s a brief breakdown:
- The term \( b^2 - 4ac \) is called the discriminant. It determines the nature of the roots.
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there is exactly one real root.
- If the discriminant is negative, there are no real roots; instead, there are two complex roots.
Understanding this formula is essential for solving any quadratic equation effectively. While it does not directly tell the direction of a parabola, knowing how to find the roots adds more context and helpful information regarding the behavior of the quadratic function on the graph.
\( ax^2 + bx + c = 0 \).
The formula helps to find the roots (or solutions) of the quadratic equation and is expressed as:
\[ x = \frac{-b \, \pm \, \sqrt{b^2 - 4ac}}{2a} \]
Here’s a brief breakdown:
- The term \( b^2 - 4ac \) is called the discriminant. It determines the nature of the roots.
- If the discriminant is positive, there are two distinct real roots.
- If the discriminant is zero, there is exactly one real root.
- If the discriminant is negative, there are no real roots; instead, there are two complex roots.
Understanding this formula is essential for solving any quadratic equation effectively. While it does not directly tell the direction of a parabola, knowing how to find the roots adds more context and helpful information regarding the behavior of the quadratic function on the graph.
Graph Analysis
Analyzing the graph of a quadratic function provides a visual understanding of its properties and behavior. Here's what you need to focus on:
For the given function \( f(x) = x^2 + 5 \):
- The vertex is at (0, 5), since there is no linear term (\( b = 0 \)).
- The axis of symmetry is the vertical line \( x = 0 \).
- The y-intercept is at (0, 5).
- Since the value of \( c \) is greater than zero and \( a > 0 \), the parabola does not intersect the x-axis, meaning it has no real x-intercepts.
Analyzing these components helps to sketch the graph accurately and understand the function’s behavior in detail.
- Vertex: The highest or lowest point on the graph, depending on the direction the parabola opens. For \( f(x) = ax^2 + bx + c \), the vertex can be found using the formula \( (-\frac{b}{2a}, f(-\frac{b}{2a})) \).
- Axis of Symmetry: A vertical line that passes through the vertex and divides the parabola into two symmetrical halves. For the function \( f(x) = ax^2 + bx + c \), it is given by \( x = -\frac{b}{2a} \).
- Y-intercept: The point where the graph intersects the y-axis, given by the value of \( c \). This is always at the point \( (0, c) \).
- X-intercepts: The points where the graph intersects the x-axis, which are the roots of the quadratic equation \( ax^2 + bx + c = 0 \). These can be found using the quadratic formula.
For the given function \( f(x) = x^2 + 5 \):
- The vertex is at (0, 5), since there is no linear term (\( b = 0 \)).
- The axis of symmetry is the vertical line \( x = 0 \).
- The y-intercept is at (0, 5).
- Since the value of \( c \) is greater than zero and \( a > 0 \), the parabola does not intersect the x-axis, meaning it has no real x-intercepts.
Analyzing these components helps to sketch the graph accurately and understand the function’s behavior in detail.
Other exercises in this chapter
Problem 11
Solve each equation by using the quadratic formula. $$y^{2}+y=6$$
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For each given pair of numbers find a quadratic equation with integral coefficients that has the numbers as its solutions. See Example 1. $$i \sqrt{2},-i \sqrt{
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